Answer:

Step-by-step explanation:
I assume that it is a composed figure formed by a triangle and a square.Since you did not give the dimensions of the triangle and the dimensions of the square, I will giveyou a general explanation about how to solve this exercise.
The area of the shape will be the sum of the the area of the square and the area of the triangle.
Then, you need to remember that the area of a triangle can be calculated with the following formula:

Where "b" is the base and "h" is the height.
And the area of a square can be found with this formula:

Where "s" is the length of any side of the square.
Therefore, the area of the shape will be

X²-4x+(4/2)²-(4/2)²+13=0
x²-4x+4-4+13=0
-4 should be added
Mark brainliest please
So you have a right angle triangle. You need to use trig for this, as you have two values you can figure out a third.
You know that you have
90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle
sin19 = x/15
15sin19 = x
x = 2.2
Now do Pythagoras c^2-b^2=a^2
a = 14.8
So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)
Length times width (48) 48 convert to sq meters is around 4.45935