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boyakko [2]
3 years ago
15

A sample of 8 golf balls is randomly selected and the following weights are measured in grams. Give a point estimate for the pop

ulation variance. Round your answer to three decimal places. 45.15,45.12,45.19,45.08,45.21,45.17,45.14,45.24
Mathematics
1 answer:
Oxana [17]3 years ago
6 0

Answer:

\bar X = 45.1625

And the sample variance is given by:

s^2 = \frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}

And replacing we got:

s^2= 0.00262\approx 0.003

And this one is the best estimator for the population variance \sigma^2

Step-by-step explanation:

For this case we have the following data:

45.15,45.12,45.19,45.08,45.21,45.17,45.14,45.24

The first step would be calculate the sample mean given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = 45.1625

And the sample variance is given by:

s^2 = \frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}

And replacing we got:

s^2= 0.00262\approx 0.003

And this one is the best estimator for the population variance \sigma^2

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