Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
Whelan
Step-by-step explanation:
stone duck twice is jacky tabby each dvi runs rgb us esc hoc TLC rig TJ DJ gabi FCC fold EU
Luis = 6/7
Marrisa = 5/9
Federico = 11/10 = 1 1/10
Greatest fraction = 1 1/10
Answer: Frederico raised the most.
Answer:
float
Step-by-step explanation:
density = mass/voume
3g/6c.m. ^3
0.5g/c.m.^3 = 0.5g/mL^3
Since the density of water is about 1g/mL^3 and 0.5g/mL^3 is less than that, it will float
You can buy 6 bags of forks and 8 bags of spoons. All you simply have to do is find the common multiple of the two. You can just multiply them both if you can’t find any others or it’s easier
