Answer:
There is a 1/64 possibility.
Step-by-step explanation:
Since the probability of selecting student 1's number is 1/8 and then replacing it leaves us with still 8 numbers to choose from, so student 8's probability of being selected is also 1/8. Multiplying these two gives P=1/64, since (1/8)^2 = 1/64.
Hope this helps!
For this simulation, there are 5 numbers that we can draw. One of the numbers will result in seeing the groundhog. (1/5 or 0.20) To find the probability that Jay will see the groundhog 4 years in a row, we would use the following equation: 1/5•1/5•1/5•1/5
We would multiply the odds of getting a certain outcome by the number of time we want that outcome.
The odds that Jay will see the groundhog for the next for years is 0.0016, or .16%.
Answer:
27
Step-by-step explanation:
25,16,21,30
Put the numbers in order from smallest to largest
16,21,25,30
The median is the middle and the median is 25 so the new number must be 25 or larger
The only number on the the list that is 25 or largest is 27
20 divided by 0 isn’t possible :)
