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aksik [14]
3 years ago
9

$4,000 cost is what percent (%) of $6,000 sales price?

Mathematics
2 answers:
Rus_ich [418]3 years ago
7 0

Answer:

66.67%

Step-by-step explanation:

cost price is given as = $4,000

Sale price is given as = $6,000

Therefore, percentage of cost price to the sale price

\frac{\text{cost price}}{\text{sale price}}\times 100

= \frac{4000}{6000}\times 100

= \frac{4}{6}\times 100

= \frac{400}{6}

= 66.67%

puteri [66]3 years ago
4 0
IT SHOULD BE 240,000

OR 

66.667%
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tensa zangetsu [6.8K]

Answer:

y=-2x+12

Step-by-step explanation:

This is an equation in slope-intercept form:

y=mx+b (where m is the slope and b is the y-intercept)

We are given the slope, -2.

y=-2x+b

We plug in the values (5,2):

2=(-2)*5+b

2=-10+b

b=12

The equation is:

y=-2x+12

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3 years ago
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The graph below shows the design for the front view of a doghouse that Jeremy plans to build. If each square on the graph repres
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Based on the graph, the total perimeter of the doghouse Jeremy plans to build s 28 feet (twenty-eight feet).

<h3>What is the perimeter?</h3>

This is the total distance of all the sides in a shape. Due to this, the general formula is:

  • Perimeter = side + side + side.

<h3>What is the perimeter of the doghouse?</h3>
  • Horizontal side: 8 feet
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8+10+10= 28 feet.

Note: This question is incomplete because the graph is missing; here is the graph:

Learn more about perimeter in: brainly.com/question/6465134

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7 0
2 years ago
Can u please help me with this 2 problem please
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<h2>19.</h2><h3>Given</h3>
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  • window width and height are 11 in and 18 in, respectively
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<h3>Find</h3>
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The proportional relation can be written as

... (building width)/(building height) = (window width)/(window height)

Multiplying by (building height) gives

... (building width) = (building heigh) × (window width)/(window height)

... (building width) = 108 ft × (11 in)/(18 in)

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<h2>21.</h2><h3>Given</h3>
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The distances are in proportion, so

... (map distance) : (actual distance) = 1.5 in : 5 mi

Multiplying by (5 mi)/(1.5 in)×(actual distance), we have

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