Mr Thompson plans to invest $7,500 in a savings account that earns 2.75% simple annual interest. If he makes no other deposits o
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The 85th percentile is a probability of 0.85 and its location is shown in the bell curve below
We need to look up on the z-table the value of z when P(Z<z) = 0.85 or P(Z>z) = 0.15
Value of z-score when p-value P(Z>z) = 0.15 is z = 1.0364
Next step is to use the formula of z-score to work out X
z-score = (X-μ) / σ
1.0364 = (X-80) / 15
1.0364 × 15 = X - 80
X = 15.546 + 80
X = 95.5
Most likely score that Ashley gets is 95.5
We need to look up on the z-table the value of z when P(Z<z) = 0.85 or P(Z>z) = 0.15
Value of z-score when p-value P(Z>z) = 0.15 is z = 1.0364
Next step is to use the formula of z-score to work out X
z-score = (X-μ) / σ
1.0364 = (X-80) / 15
1.0364 × 15 = X - 80
X = 15.546 + 80
X = 95.5
Most likely score that Ashley gets is 95.5