Question

Uh need a bit of help with this question

Answer 1

When we multiply two powers of a common base, we add the exponents.  That's the familiar rule

$a^m a^n = a^{m+n}$

So here

$13^8 \times 13 ^{-4} = 13^{8+ -4}= 13^4$

Answer: C

Answer 2

a^m a^n = a^{m+n}

So here

13^8 \times 13 ^{-4} = 13^{8+ -4}= 13^4

Answer: C