1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LUCKY_DIMON [66]
3 years ago
11

Can someone help me asap​

Mathematics
1 answer:
scoundrel [369]3 years ago
7 0
M=4/5
you find a point that is exact like (20,60)
You might be interested in
Please Help me Put the numbers to order them from least to greatest. -2.86 -0.37 0.91 0.19 1.46
svp [43]

Answer:

Switch .91 and .19 and you're good

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
I am pretty sure I know the answer but I need to be certain. Please answer and give explanation if possible.
creativ13 [48]

Answer:

Vertical opposite angles are the same so the answer is D.

8 0
3 years ago
Select the correct answer.
skad [1K]

Answer:

D

Step-by-step explanation:

7 is it because it is positive

6 0
3 years ago
In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they spent, on average, $54 per hour
Lesechka [4]

Answer:

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=54 represent the sample mean  

\mu population mean (variable of interest)

\sigma=21 represent the sample standard deviation

n=16 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=1-0.9=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

4 0
3 years ago
Please help which graph
katen-ka-za [31]
Which ever graph looks like this

5 0
3 years ago
Other questions:
  • The mass of the Eiffel Tower is about 9.16 ⋅ 10^6 kilograms. The mass of the Golden Gate Bridge is 8.05 ⋅ 10^8 kilograms. Approx
    12·2 answers
  • The length of a rectangle is 4 feet more than the width. If the perimeter is 20 ft. What is the length of the rectangle?
    12·1 answer
  • How do I order 1/7,-1/7 and 0 from least to greatest ?
    10·2 answers
  • 1.which expression is equivalent to (4-3i) 2
    11·1 answer
  • Sammy has three times as many nickels as quarters and twice as many dimes as quarters if he has 1.80 all together then how many
    14·1 answer
  • A cereal box has a volume of 441 cubic inches. Its height is 12 inches, its width is x inches, and its length is (x+7) inches. W
    15·1 answer
  • Matthew bought a jersey, a pennant, and a hat. He paid with a $50 bill and some money he borrowed from his friend. If Matthew go
    8·2 answers
  • 5x( 4y2 + 5z) – (4y2 + 52
    13·1 answer
  • Match each step with the correct expression to factor s2 + 78 + 6 by using the decomposition method.​
    10·1 answer
  • I know I keep asking for help but I literally just got put back in my right grade pls help
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!