The value of h is exactly the axis of symmetry. So when h changes, it completely changes the line of symmetry. This is because the vertex is (h, k) and the x value of the vertex is always equal to the line of symmetry in a quadratic.
Changing the k value does nothing to the line of symmetry. This is because it is just moving the graph up and down, which doesn't change the symmetry of a parabola.
Answer:
3789)√××{2664863 %/++631%
5545845433%
8766461%. -/
Answer:
C) x2 + x = 306
Step-by-step explanation:
x2 + x = 306
x2 + x - 306 = 0
x2 + 18x - 17x + 18 * (-17) = 0
x ( x + 18) - 17 (x +18) =0
(x + 18) (x - 17 ) = 0
x = -18 or 17
Answer:
The number of palindromes is
when n is even and
when n is odd
Step-by-step explanation:
From the question we are told that
The length of the string is ![n](https://tex.z-dn.net/?f=n)
Generally palindrome is evaluated by considering the first part of a string
When the the length of the string is an even number then
it means that the first part of the string is ![\frac{n}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D)
Hence the number of bit strings of length n that are palindromes is evaluated as
![p(n_{even }) = 2^{\frac{n}{2} }](https://tex.z-dn.net/?f=p%28n_%7Beven%20%7D%29%20%3D%20%202%5E%7B%5Cfrac%7Bn%7D%7B2%7D%20%7D)
But When the the length of the string is an odd number then
it means that the first part of the string is ![\frac{n-1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bn-1%7D%7B2%7D)
Hence the number of bit strings of length n that are palindromes is evaluated as
![p(n_{odd }) =2^{\frac{n -1}{2} +1 } = 2^{\frac{n +1}{2} }](https://tex.z-dn.net/?f=p%28n_%7Bodd%20%7D%29%20%3D2%5E%7B%5Cfrac%7Bn%20-1%7D%7B2%7D%20%2B1%20%7D%20%3D%202%5E%7B%5Cfrac%7Bn%20%2B1%7D%7B2%7D%20%20%7D)
Generally each bit could be either 0 or 1
Hence the number of palindromes is
when n is even and
when n is odd
The area is 864 square, or 6 square feet.