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allsm [11]
3 years ago
13

A catalog of scientific equipment states that the lens of a particular telescope has a circumference of 6.28 yards. What is the

lens's area? Use 3.14 for ​.
Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0

The area of lens is 3.14 square yards.

Step-by-step explanation:

Given,

Circumference of lens = 6.28 yards

Circumference = 2πr

6.28=2*3.14*r\\6.28=6.28r\\6.28r=6.28

Dividing both sides by 6.28

\frac{6.28r}{6.28}=\frac{6.28}{6.28}\\r=1

Area of lens = πr²

Area of lens = 3.14*(1)^2=3.14*1

Area of lens = 3.14 square yards

The area of lens is 3.14 square yards.

Keywords: area, circumference

Learn more about area at:

  • brainly.com/question/10414011
  • brainly.com/question/10483199

#LearnwithBrainly

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D because coefficient is the number next to the variable and 7 is the coefficient to the fifth power
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3 years ago
Is the following expression true or false? [x^2 + 8x + 16] · [x^2 – 8x + 16] = (x2 – 16)^2
Vilka [71]

(x^{2} +8x+16)(x^{2} -8x+16)\\(x+4)^{2} (x-4)^{2} \\(x^{2}-16)^{2} \\

it is true; just work them out, you should get what they got :))

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Read 2 more answers
3x−(2x+1) for x=7 5/13
marusya05 [52]

Answer:

83/13 or 6.3846

Step-by-step explanation:

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8 0
4 years ago
Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the
Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0
4 years ago
Pleaseee I needed the answerrr now​
loris [4]

Step-by-step explanation:

Given,

a=3,b=2,c=5

a)a(b+c)

=3(2+5)

=3×7

=21.

B)2ac^2

=2×3×(5)^2

=6×25

=150

5 0
3 years ago
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