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Gekata [30.6K]
3 years ago
8

A dream club charges $60 for the first month of membership, and $2 less each month after that. (Yes, after a while the dream clu

b starts paying money to members instead of charging them :)). What is the total membership for a year? For 5 years?
Mathematics
1 answer:
liq [111]3 years ago
6 0

Answer:

Total membership for a year is $588

Total membership for 5 years is $60

Step-by-step explanation:

This is an arithmetic sequence of the form:

60, 58, 56, 54 ...

The first term is a = 60

the common difference is d = -2

We need to find the total member cost for a year, that is the sum of all the first 12 terms. We use the formula of sum of arithmetic sequence shown below:

S_n=\frac{n}{2}[2a+(n-1)d]

Where

a is first term

n is the number of term [here, 12]

d is common difference

From what we know, we can find:

S_n=\frac{n}{2}[2a+(n-1)d]\\S_{12}=\frac{12}{2}[2(60)+(12-1)(-2)]\\S_{12}=588

Total membership for a year is $588

Now to find this for 5 years, we have to find 5*12 = 60 months.

So S_60, formula and find:

S_n=\frac{n}{2}[2a+(n-1)d]\\S_{60}=\frac{60}{2}[2(60)+(60-1)(-2)]\\S_{60}=60

Total membership for 5 years is $60

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Answer:

The factors of  2(x+y)^2-9(x+y)-5 is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=>2(x+y)^2-9(x+y)-5

To Find:

The factors of the polynomial =?

Solution:

Lets assume  k = (x+y)

Then 2(x+y)^2-9(x+y)-5 can be written as 2k^2-9k-5

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k =\frac{-b\pm\sqrt{(b^2-4ac}}{2a}

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Substituting the values, we get

k =\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}

k =\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}

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Solving the RHS we get

\frac{2}{2}(k-5)(2k+1)

(k-5)(2k+1)

Substituting k = x+y

((x+y)-5)(2(x+y+1)

((x+y)-5)(2x+2y+1)

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