D= square root [(x2-x1)^2 + (y2-y1)^2]
What is the solution of VX-4+5=2?
2 answers:
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Answer:
PQ = 16
Step-by-step explanation:
Using the cosine ratio in the right triangle and the exact value
cos60° = , then
cos60° = =
=
=
( cross- multiply )
PQ = 8 × 2 = 16
To find y, divide the first equation by 2.
y = 4
To find x, use that value for y in the second equation. Add 4, then divide by 2.
15·4 = 2x -4
60 +4 = 2x
64/2 = x = 32
The solution is (x, y) = (32, 4).
y = 4
To find x, use that value for y in the second equation. Add 4, then divide by 2.
15·4 = 2x -4
60 +4 = 2x
64/2 = x = 32
The solution is (x, y) = (32, 4).