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4 years ago

What is the height of a cylinder with a volume of 936 times 3.14 cubic inches and a diameter of 24 inches?

Mathematics

2 answers:

Marina86 [1]4 years ago

4 0

Answer:

6.5

Step-by-step explanation:

S_A_V [24]4 years ago

3 0

H= .6.5

V=πr^2h

h= v/πr^2 = 2940.5/π*12^2 = 6.49993 = 6.5

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ANTONII [103]

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3 years ago

VashaNatasha [74]

Answer:

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Step-by-step explanation

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2 years ago

Evaluate: (x^2-1)/(x-1) if x goes to 1?

egoroff_w [7]

Step-by-step explanation:

$\displaystyle \lim_{x \to 1} \dfrac{(x^2 - 1)}{(x-1)} = \lim_{x \to 1} \dfrac{(x - 1)(x+1)}{(x-1)}$

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3 years ago

Select the correct answer. Given: `Delta`ABC, where AB = BC Prove: `"m"/_BAC = "m"/_BCA` Statement Reason 1. Let `Delta`ABC be a

Leto [7]

Since BD is the angle bisector of ∠ ABC,

∠ ABD = ∠ CBD --- (1)

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BD = BD (common side)

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AB = BC (Given)

Hence, Δ ABD ≅ Δ CBD (SAS Rule).

5 0

3 years ago

4) Sandeep, Hee, Sara, and Mohammad play euchre with a standard deck consisting of 24 cards (A, K, Q, J, 10, and 9 from each of

Keith_Richards [23]

Answer:

1.19685 × 10¹⁶

Step-by-step explanation:

From the given information.

Since each players receives 5 cards; then = 5 * 4 = 20

Now, the process to go about this is to first select 5 cards out of 24 that goes to player 1. Then from the remaining 19, we can select another 5 cards that goes to player 2, etc. until 4 cards are left, out of which one is remained faced up. Thus, the 4 sets of 5 cards selected can be shuffled in 4! ways.

∴

No fo ways = $^{24}C_5 \times ^{19}C_5 \times ^{14}C_5 \times ^{9}C_5 \times 4! \times ^{4}C_1$

$= \dfrac{24!}{5!(24-5)!}\times \dfrac{19!}{5!(19-5)!}\times \dfrac{14!}{5!(14-5)!}\times \dfrac{9!}{5!4!}\times 4! \times \ \dfrac{4!}{1!(4-1)!}$

$= \dfrac{24!}{5!^4}\times 4$

= 1.19685 × 10¹⁶

6 0

3 years ago