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tiny-mole [99]
3 years ago
11

A particle executes simple harmonic motion with an amplitude of 2.18 cm.

Physics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

The positive displacement from the midpoint of its motion at the speed equal one half of its maximum speed is 3.56 cm.

Explanation:

Maximum speed is  :

                          v (max) = Aω

Speed v at any displacement y is given by  

v^{2} = w^{2} (A^{2} - y^{2})   ........................................................  i

And,

               v = \frac{1}{2} v (max)  

          or,  2 × v = Aω     ....................................................   ii

Eliminating  ω from equations i and ii,

                       \frac{1}{4} A^{2}  w^{2}  =  w^{2}  ( A^{2}  - y^{2})

                     or, y^{2} =  (\frac{3}{4}) A^{2}  =(\frac{3}{4}) 2.18^{2}

                    or,  y =  3.56 cm.

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Explanation:

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3 years ago
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A high school physics student is sitting in a seat read-
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The equilibrium condition allows finding the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Newton's second law gives the relationship between force, mass and acceleration of bodies, in the special case that the acceleration is is zero equilibrium condition.

            ∑ F = 0

Where F is the external force.

The free body diagram is a diagram of the forces on bodies without the details of the shape of the body, in the attached we can see a diagram of the forces.

Let's analyze the force on the chair.

            N_{chair} - W_{chair} - W_{student} = 0 \\ \\N_{chair} = W_{chair} + W_{student}

Let's analyze the forces on the student.

          N_{student} - W_{student} = 0  \\N_{student} = W _{student}

           

In conclusion using the equilibrium condition we can find the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Learn more here: brainly.com/question/18117041

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2 years ago
An object of mass m is lowered at constant velocity at the end of a string of negligible mass. As it is lowered a vertical dista
bezimeni [28]

Answer:

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The conserved form of the equation is given by

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In that form the total mechanical energy is conserved.

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3 years ago
if you double the mass of an object while leaving the net force unchanged what is the result of the acceleration
butalik [34]
Force = mass*acceleration
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If you double the mass then acceleration will be halved in order for the equation to still equal.

New acceleration = Force/(2)mass
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