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ira [324]
3 years ago
11

Ammonia reacts with oxygen according to the equation 4nh3(g)+5o2(g)→4no(g)+6h2o(g),δhrxn=−906 kj calculate the heat (in kj) asso

ciated with the complete reaction of 155 g of nh3. express the heat in kilojoules to three significant figures.
Physics
2 answers:
Dafna11 [192]3 years ago
8 0
<span>155 g of NH3 = 9.10 moles Heat released = 9.10 moles * [ -9 kJ/4 moles NH3 ] = -20.5 kJ (278 g NH3) / (17.03056 g NH3/mol) x (-906 kJ / 4 mol NH3) = -3697 kJ [or maybe omit the minus sign]. Its a HESS reaction.</span>
Lesechka [4]3 years ago
3 0

Answer: 2.06 × 10 ³ kJ = 2,060 kJ


Explanation:


1) Balanced chemical equation (given)


4NH₃ (g) + 5O₂ (g) → 4NO (g) + 6H₂O (g), δH rxn = − 906 kJ


2) Calculate the number of NH₃ moles in 155 g


i) molar mass of NH₃ = 14.007 g/mol + 3×1.008 g/mol = 17.031 g/mol


ii) number of moles = mass in grams / molar mass = 155 g / 17.031 g/mol = 9.10 mol of NH₃


3) Caculate the energy using proportions with the mole /energy ratio from the balanced chemical equation:


4 moles NH₃ / (-906 kJ) = 9.10 mol NH₃/ x


⇒ x = 9.10 mol NH₃ × (-906 kJ) / 4 mol NH₃ = - 2,061.15


Which rounded to three significan figures is 2.06 × 10 ³ kJ = 2,060 kJ

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