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2 years ago

a rock is dropped from a height of 80 m and is in free fall what is the velocity of as it reaches the ground 4.0 seconds later

Physics

1 answer:

Marta_Voda [28]2 years ago

8 0

Velocity = displacement (distance)/time

v=80m/4s

v=20m/s

velocity = 20 meters per second

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Why are Big cinema hall are carpeted and their walls are made of some rough materials

Vadim26 [7]

Answer:

because these materials absorb the sound and do not allow them from going out of as, some times the sound can be a trouble to the people.

Explanation: Hope this helps!

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2 years ago

A 8.01-nC charge is located 1.87 m from a 4.50-nC point charge. (a) Find the magnitude of the electrostatic force that one charg

valkas [14]

Answer:

Explanation:

Given

$q_1=8.01\ nC$

$q_2=4.50\ nC$

distance between the charges is given by $d=1.87\ m$

Electrostatic force between the charges is given by

$F_{12}=F_{21}=\frac{kq_1q_2}{d^2}$

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2 years ago

A woman with mass 50 kg is standing on the rim of a large disk that is rotating at 0.80 rev/s about an axis through its center.

My name is Ann [436]

Answer:

angular momentum, $L=1.4\times 10^4\ kg-m^2/s$

Explanation:

Given that,

Mass of the woman, m = 50 kg

Angular velocity of the disk, $\omega=0.8\ rev/s=5.02\ rad/s$

Mass of the disk, m' = 2670 kg

Radius of the disk, R = 4 m

We need to find the magnitude of the total angular momentum of the woman–disk system. The moment of inertia of the system is equal to the sum of moment of inertia of women and the moment off inertia of the disk.

$I=mR^2+\dfrac{1}{2}m'R^2\\\\I=R^2(m+\dfrac{1}{2}m')\\\\I=(4)^2\times (50+\dfrac{1}{2}\times 270)\\\\I=2960\ kg-m^2$

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$L=I\omega\\\\L=2960\times 5.02\\\\L=14859.2\ kg-m^2/s$

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So, the magnitude of the total angular momentum of the woman–disk system is $1.4\times 10^4\ kg-m^2/s$ . Hence, this is the required solution.

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2 years ago

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fenix001 [56]

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2 years ago

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Answer:

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Explanation:

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2 years ago