All categories

3 years ago

I need help? i don’t understand this ?

Mathematics

1 answer:

xxMikexx [17]3 years ago

8 0

Answer:

the answer is ab

Step-by-step explanation:

you should go to the x axis and go to the four then go up 7 and it should land on the line in between a and b

Let me know if this helps :)

You might be interested in

Savannah wants to purchase C dozen cupcakes for $2.50 each and B boxes of brownies for $3.25 each. She can spend at most $35. Wh

Vika [28.1K]

Answer:

14 packs of cupcakes and 10 packs of brownies!

Step-by-step explanation:

Hoped I helped :)

6 0

3 years ago

PLEASE HELP

kaheart [24]

Answer:

use pressure =Force /area

Step-by-step explanation:

12000N/1.08

7 0

3 years ago

Which is equivalent to 1/4

Alex73 [517]

Answer:

2/8, 4/16, and so on

Step-by-step explanation:

1/4 could be equal to many numbers as long as when you simplify it down it will reach 1/4

4 0

3 years ago

Read 2 more answers

Circle X has radius r X = 6 units and circumference C X = 12 π units. Circle Y has circumference C Y = 6 units. Which equation i

slega [8]

Answer:

$ry=\frac{rx}{2\pi }$

Step-by-step explanation:

we know that

The circumference of a circle is equal to

$C=2\pi r$

we have

<em>Circle X</em>

$rx=6\ units$

$Cx=12\pi\ units$

<em>Circle Y</em>

$Cy=6\ units$

Find the radius ry

we know that

$Cy=2\pi ry$

substitute the value of Cy

$6=2\pi ry$

$ry=\frac{6}{2\pi }$

Remember that the value of rx is $rx=6\ units$

substitute

$ry=\frac{rx}{2\pi }$

6 0

3 years ago

Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion do

V125BC [204]

Answer:

Step-by-step explanation:

It is given that

$\Delta=\begin{vmatrix}3&0&3\\2 &3&3\\0 &4&-2\end{vmatrix}$

By cofactor expansion across the first row, we get

$\Delta=a_{11}C_{11}+a_{12}C_{12}+a_{13}C_{13}$

$\Delta=3\left[(-1)^{1+1}\begin{vmatrix}3&3\\4&-2\end{vmatrix}\right]+0\left[(-1)^{1+2}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{1+3}\begin{vmatrix}2&3\\0&4\end{vmatrix}\right]$

$\Delta=3\left[-18\right]+0\left[(-1)(-4)\right]+3\left[8\right]$

$\Delta=-54+0+24$

$\Delta=-30$

Therefore, the value of determinant is -30.

By cofactor expansion across the second column, we get

$\Delta=a_{12}C_{12}+a_{22}C_{22}+a_{32}C_{32}$

$\Delta=0\left[(-1)^{2+1}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{2+2}\begin{vmatrix}3&3\\0&-2\end{vmatrix}\right]+4\left[(-1)^{3+2}\begin{vmatrix}3&3\\2&3\end{vmatrix}\right]$

$\Delta=0\left[(-1)(-4)\right]+3\left[(-6)\right]+4\left[(-1)3\right]$

$\Delta=-18-12$

$\Delta=-30$

Therefore, the value of determinant is -30.

7 0

4 years ago