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3 years ago

I need help? i don’t understand this ?

Mathematics

1 answer:

xxMikexx [17]3 years ago

8 0

Answer:

the answer is ab

Step-by-step explanation:

you should go to the x axis and go to the four then go up 7 and it should land on the line in between a and b

Let me know if this helps :)

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If tan theta = 10/13 and cos theta > 0 then sin2theta is what ?

svetoff [14.1K]

$sin2\alpha = \frac{260}{269}$

<u>Step-by-step explanation:</u>

We have , $Tan\alpha = \frac{Perpendicular}{Base} = \frac{10}{13}$ ,

We know that $sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }$

Substituting values of P & B , $sin\alpha = \frac{10}{\sqrt{10^{2} + 13^{2}} } = \frac{10}{\sqrt{269} }$

Now , $sin2\alpha = 2sin\alpha cos\alpha = 2sin\alpha \sqrt{1 - (sin\alpha)^{2} }$

⇒ $sin2\alpha =$ $\frac{10}{\sqrt{269} }$ × $\sqrt{1 - (\frac{10}{\sqrt{269} })^{2} }$ ×2

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{269 - 100}{269} } )$

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{169 }{269} } )$

⇒ $sin2\alpha = \frac{260}{\sqrt{269} }( \sqrt{\frac{1}{269} } )$

⇒ $sin2\alpha = \frac{260}{269}$

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3 years ago

Consider the equation y = 2x + 3. Drag the red point on the graph to represent the

soldier1979 [14.2K]

Answer:

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3 years ago

Solve for t: 3x8= t+15

hodyreva [135]

Hey there!

I'm going to set up the equation slightly different.

$(3)(8)=t+5\\24=t+5\\t+15=24\\t+15-15=24-15\\t = 9 \checkmark$

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Subtract 5b − 3c from −8a − 2b − 10c

erik [133]

Answer:

-8a - 7b - 7c

Step-by-step explanation:

-8a - 2b - 10c - (5b - 3c)

Negate 5b and -3c

-8a - 2b - 10c - 5b + 3c = -8a - 7b - 7c

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Write this number in word form 3,388,198

Minchanka [31]

Three million three hundred eighty eight thousand one hundred ninety eight.

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