Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
Assuming the exponent is supposed to be "^2" your equation will read:
4x² + 8x - 5
It must set equal to y to be a valid function and the y must be set equal to zero to find x-intercepts.
4x² + 8x - 5 = 0
4x² - 2x + 10x - 5 = 0
2x(2x - 1) + 5(2x - 1) = 0
(2x + 5)(2x - 1) = 0
Set each binomial equal to zero.
2x + 5 = 0
2x = 0 - 5
2x = - 5
Divide both sides by 2
x = - 5/2
2x - 1 = 0
2x = 0 + 1
2x = 1
x = 1/2
Your x-intercepts are x = - 5/2, 1/2 or (- 5/2, 0) and (1/2, 0)
A really big one that is larger that the acute angel
Answer:
Step-by-step explanation:
All the sides are complete, hence we can use the information given to find just 1 triangle
Triangles
From the given information, we have that:
m<B = pi/6 = 30 degres
c = 10
b = 5
This shows that we can use the cosine rule to find the third side b of the triangle. Since all the sides are complete, hence we can use the information given to find just 1 triangle
The answer to this is 720000
