3 years ago

Write the fraction 5/6 as a percent rounded to the nearest hundredth of a percent where necessary

1 answer:

6 0

<span>Dividing 5 by 6, multiplying by one hundred (to get a percent), then rounding the hundreth of a percent, 83.33%</span>

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vladimir2022 [97]

The confidence interval is
$0.59\pm0.081$

We first find p, our sample proportion. 118/200 = 0.59.

Next we find the z-score associated with this level of confidence:
Convert 98% to a decimal: 98% = 98/100 = 0.98
Subtract from 1: 1-0.98 = 0.02
Divide by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 2.33.

The margin of error (ME) is given by
$ME=z\sqrt{\frac{p(1-p)}{n}}
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This gives us the confidence interval
$0.59\pm0.081$

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3 years ago