1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Jobisdone [24]
3 years ago
6

The length of a side of an equilateral triangle is x-4.5.First express it's perimeter as a sum. Next express its perimeter as a

product. Explain why the two expressions are equvalent.
Mathematics
1 answer:
LiRa [457]3 years ago
8 0
The sides of an equilateral triangle are same. So if one of the sides is (x-4.5), all the sides are (x-4.5). 
Let the sides are a=(x-4.5), b=(x-4.5), c=(x-4.5)

1. Perimeter(as sum) = a+b+c
                                    =  (x-4.5)+(x-4.5)+(x-4.5)
                                    = x+x+x-4.5-4.5-4.5
                                    = 3x - 13.5
2. Perimeter (as product) = 3×a    
                                     = 3×(x-4.5)
                                     = 3×x - 3×4.5
                                     = 3x - 13.5
(you can write 3×b or 3×c also as a=b=c.)

<em>Both perimeter as sum and perimeter as product are same as adding a number three times is the same as multiplying it by 3.</em>
You might be interested in
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions
Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector \vec{v} in some vector space \mathbb R^n we have

\vec{v} = \langle a,b\rangle

This is the component form. I don't like that way. It is probably used in high school, but

\vec{v} =  \begin{pmatrix} a\\ b\\ \end{pmatrix}

is preferable because the inner product on \mathbb R^n is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as \vec{v} = 2i+2j

4.

For this question, I think you meant

vectors

\vec{u_1} = (-8, 12)

\vec{u_2}  = (13, 15)

Once

\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}

Considering that the dot product is

\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76

and the norm of \vec{u_1} is ||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}

and the norm of \vec{u_2} is ||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}

Thus,

\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}

\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)

3 0
3 years ago
PLEASE PLEASE HELP ME
Alexus [3.1K]
Y=-2x-2 it is the only one that is perfectly perpendicular and passes through (-3,4)
3 0
3 years ago
Greatest common factor M^3n and 5m^5n^2
xenn [34]

Answer:

m³n

Step-by-step explanation:

8 0
3 years ago
Rename 1/2 and 1/5 using the least common denominator.
gladu [14]
C multiply 1/2 by 10 and 1/5 by 2
3 0
3 years ago
The area of Maxine's living room is 88 square feet. The length of the room is 3 feet longer than the width. Which quadratic equa
GaryK [48]

Answer:

B. Because x(x+3) is x^2+3x

6 0
3 years ago
Other questions:
  • Simplify to create an equivalent expression -5(3p+3)+9(-7+p)
    12·1 answer
  • How many times can 3 go into 400
    7·2 answers
  • Can anyone solve this problem please help me
    15·1 answer
  • Ten percent of a number equals 50.What is the number?
    5·2 answers
  • Need help please on Pre Calculus!!! Directions: verify each identity
    9·1 answer
  • HELP PLEASE????<br> ???????
    10·2 answers
  • 76% of the grade 5 pupils are girls.Express 76% as decimal.
    7·2 answers
  • Find the area of the shape below.<br> 10 cm<br> 27 cm<br> 9 cm<br> 24 cm
    7·2 answers
  • 3 of 4
    7·1 answer
  • At a factory that produces pistons for cars, Machine 1 produced 174 satisfactory pistons and 116 unsatisfactory pistons today. M
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!