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aniked [119]
3 years ago
15

From home, Mary’s work is two thirds along the way to training. Training is 2.5km from work. Mary normally goes to work, then tr

aining and then home again. However, today she forgot her shoes. How far will Mary travel in total today if she has to go home before training to get her shoes?

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0
First thing to do is to illustrate the problem, Since it was mentioned that work was along the way to training, the order is shown in the picture. Mary's home and workplace are nearer compared to her training center. It is also mentioned that the distance between work and home, denoted as x, is 2/3 of the total distance from home to training. The total distance is (x + 2.5). Thus,

x = 2/3(x+2.5)
x = 2/3 x + 5/3
1/3 x = 5/3
x = 5 km

Thus, the distance from home to work is 5 km. This means that Mary has to walk this distance twice to return home to get her shoes. Then, she will travel again the total distance of 5+2.5 = 7.5 km to get to her training center. So,

Total distance = 2(5km) + 7.5 km
Total distance = 17.5 km

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The steps Quentin took to evaluate the expression 3m - 3+3 when m = 8
kicyunya [14]

Answer:

Subtracted 3 from (24+3)

Step-by-step explanation:

3m - 3 + 3

24 - 3 + 3

Since the adding and subtracting go left to right, you can do them in that order.

21+3 = 24.

Now which one gives us 24?

(24+3) - 3

3 0
3 years ago
(m? - 5 m +6 )<br>÷(m - 2)​
leonid [27]

Answer:

(m? - 5 m +6 )  ÷ (m - 2)​ = \frac{m}{-5m+6} / (m - 2)

Step-by-step explanation:

Divide the first expression by the second expression.

\frac{m}{-5m+6} / (m - 2)

I hope this helps.

4 0
3 years ago
Read 2 more answers
Henry had 20 convertibles and 5 trucks in his miniature car collection. After Henry's aunt bought him some more miniature trucks
saw5 [17]

Answer:

Her aunt buy <u>75</u> trucks.

Step-by-step explanation:

Given:

Henry had 20 convertibles and 5 trucks in his miniature car collection. After Henry's aunt bought him some more miniature trucks, Henry noticed that a fifth of his collection were convertible.

Now, to find the trucks her aunt buy.

Let the total collection of Henry be x.

<em>Number of trucks Henry had in his collection = 5.</em>

<em>Number of convertibles Henry had in his collection = 20.</em>

As, Henry's \frac{1}{5} collection were convertible.

Now, to get the total number of collection:

\frac{1}{5}\ of\ x=20.

\frac{1}{5} \times x=20

<em>Multiplying both sides by 20 we get:</em>

x=100.

<em>Total collection of Henry = 100.</em>

So, the total number of trucks he had in his collection is:

<u><em>Total collection of Henry - number of convertibles Henry had in his collection.</em></u>

=100-20

=80.

<em>Hence, Henry had total 80 trucks in his collection.</em>

<em>And 5 trucks he had already in his miniature car collection.</em>

Now, to get the number of trucks her aunt buy we subtract trucks he had already in his miniature car collection from the total number of trucks in Henry's collection:

<u><em>Total number of trucks in Henry's collection - Number of trucks already in his miniature car collection.</em></u>

=80-5

=75.

Therefore, her aunt buy 75 trucks.

8 0
3 years ago
Suppose the weights of tight ends in a football league are normally distributed such that σ2=1,369. A sample of 49 tight ends wa
Darya [45]

Answer:

Step-by-step explanation:Answer Explanation

Correct answers:

$\left(241.42,\ 262.14\right)$

A 95% confidence interval for μ is (x¯−zα/2σn‾√,x¯+zα/2σn‾√). Here, α=0.05, σ=37, and n=49. Use Excel to calculate the 95% confidence interval.

1. Open Excel, enter the given data in column A, and find the sample mean, x¯, using the AVERAGE function. Thus, the sample mean, rounded to two decimal places, is x¯=251.78.

2. Click on any empty cell, enter =CONFIDENCE.NORM(0.05,37,49), and press ENTER.

3. The margin of error, rounded to two decimal places, is zα/2σn‾√≈10.36. The confidence interval for the population mean has a lower limit of 251.78−10.36=241.42 and an upper limit of 251.78+10.36=262.14.

Thus, the 95% confidence interval for μ is (241.42, 262.14).

6 0
3 years ago
Algebra 1 please help!
Leona [35]

Answer:

a. geometric

b. a<em>n</em> =  2(2)^n-1 or a<em>n</em> = 2^n

c. a<em>n+1</em> <em>= </em>a<em>n</em> x 2

Step-by-step explanation:

The sequence, 2, 4, 8, 16, 32,...

a. The sequence is geometric because there is a common ratio in the numbers of the sequence. Each number is made by multiplying the common ratio and the previous number.

b. The explicit formula that can be used to find any term is a<em>n</em> =  2(2)^n-1 or a<em>n</em> = 2^n

Note: the variable n and number 1 is written in italics to show that it should be in subscript

a<em>n</em> = a<em>1 </em>(r)n-1

With the common ratio of n being 2 and first number being 2, we have:

a<em>n</em> =  2(2)^n-1

or

a<em>n</em> = 2^n

c. The recursive formula for the sequence is a<em>n+1</em> <em>= </em>a<em>n</em> x 2

a<em>n+1</em> = a<em>n </em>x r

Plugging in the values, we have

a<em>n+1</em> <em>= </em>a<em>n</em> x 2

Your welcome, and comment if you have any questions! If you could mark this answer as brainliest, I would appreciate it very much!

5 0
2 years ago
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