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3 years ago

1. What is the circumference of the circle below? Use 3.14 for pi and Round

Mathematics

2 answers:

loris [4]3 years ago

7 0

Answer:

$C = 34.5 \ cm$

Step-by-step explanation:

Circumference of the circle is given as

$C=2\pi r$

Where r is radius of circle.

Diameter of given circle is 11 cm. We know radius is half of diameter.

$r=\frac{d}{2} = \frac{11}{2}$

Circumference can be calculated as

$C=2\pi (\frac{11}{2} )$

$C = 34.5 \ cm$

S_A_V [24]3 years ago

3 0

Answer:

22...................

Step-by-step explanation:

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Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]

JulijaS [17]

Answer:

$f_{avg}=\frac{1}{e-1}$

Step-by-step explanation:

We are given that a function

$f(x)=2lnx$

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx$

By Parts integration formula

$\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx$

u=ln x and v=dx

Apply by parts integration

$f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))$

$f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})$

$f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}$

By using property lne=1,ln 1=0

$f_{avg}=\frac{1}{e-1}$

8 0

3 years ago

Which expression is equivalent to 15x^-3z^5/3x^7z^-5 please answer spr fast

Law Incorporation [45]

Answer:

$5x^{-10}z^{10$

Step-by-step explanation:

Given

$\frac{15x^{-3}z^5}{3x^7z^{-5}}$

Required

Evaluate

$\frac{15x^{-3}z^5}{3x^7z^{-5}}$

Start by dividing 15 by 3

$\frac{5x^{-3}z^5}{x^7z^{-5}}$

Apply the following law of indices on indices x and z

$\frac{a^m}{a^n} = a^{m-n$

So, the expression becomes:

$5x^{-3-7}z^{5-(-5)$

$5x^{-3-7}z^{5+5$

$5x^{-10}z^{10$

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2 years ago

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2 years ago

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vova2212 [387]

Answer:

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3 years ago

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Answer:

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