(Closer) what's the completed variable table

QUICK! The radius of a cylindrical construction pipe is 2 ft. If the pipe is 16 ft long, what is its volume?

Alika [10]

Answer:

V=201.06 ft²

Step-by-step explanation:

V= $\pi$ r²h

V= $\pi$ 2²16

V=64 $\pi$

V=201.06

4 0

3 years ago

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if a city that currently has a population of 1000 triples in size every 8 years, what will the population be in 24 years?

Kipish [7]

Year 1 - 1000
year 8 - 3000
year 16 - 9000
year 24 - 27000

7 0

4 years ago

PLEASE HELP ME I NEED HELP

ExtremeBDS [4]

Answer:

3052.1 in³

Step-by-step explanation:

The volume of a sphere is given by the formula ...

V = 4/3πr³ . . . . r is the radius

The radius is half the diameter, so is 9 in. Then the volume is ...

V = (4/3)(3.14)(9 in)³ = 972(3.14) in³ ≈ 3052.1 in³

3 0

2 years ago

for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation

Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample proportion of defective items = 12,898

s = sample standard deviation = 7,719

n = sample size = 5

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.776 < $t_4$ < 2.776) = 0.95 {As the critical value of t at 4 degrees of

freedom are -2.776 & 2.776 with P = 2.5%}

P(-2.776 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.776) = 0.95

P( $-2.776 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $12,898-2.776 \times {\frac{7,719}{\sqrt{5} } }$ , $12,898+2.776 \times {\frac{7,719}{\sqrt{5} } }$ ]

= [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

5 0

4 years ago

I need a 4th grade strategy to solve 8,736 X 6 _____

irakobra [83]

Answer:

maybe times the 6 by the 6 and the 3 by the 6 and the 7 by the 6 and the 8 by the 6 that could work hope this helped

Step-by-step explanation: so 6x6 6x3 6x7 6x8

to get 52416

3 0

3 years ago

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