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3 years ago

PLEASE help me I need help

Mathematics

2 answers:

Alexxandr [17]3 years ago

7 0

Answer:

Step-by-step explanation:

The rest you can elimate because of obvious inferring and reasoning so process of elimination

RSB [31]3 years ago

7 0

The answer is C
x= months
y=$
Constant of proportionality (C)=y/x
x=1, y=3.5
3.5/1=3.5
x=2, y=7
7/2=3.5
x=3, y=10.5
10.5/3=3.5
x=4, y=14
14/3=3.5
x=5, y=17.5
17.5/5=3.5
C=3.5

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I need number 1 please and thank you

belka [17]

Answer:

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In your case I = 4x and II = 3

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3 years ago

A hemisphere of radius 9 sits on a horizontal plane. A cylinder stands with its axis vertical, the center of its base at the cen

ikadub [295]

Answer:

The radius and height of the cylinder of maximum volume is 9 unit and 9 unit.

Step-by-step explanation:

Given that,

Radius = 9

According to figure,

Radius of cylinder = Radius of hemisphere

Center of cylinder base is also center of sphere.

Circular top of cylinder touching the top of hemisphere.

So, Height of cylinder = radius of hemisphere

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4 years ago

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OverLord2011 [107]

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3 years ago

Tommy has a pet monkey. Every day, his monkey eats 4 apples in the morning. The monkey also eats two bananas for every banana th

vekshin1

If you would like to write an equation to describe the following situation, you can do this like this:

4 apples in the morning ... 4
x ... the number of bananas Tommy eats
2 bananas for every banana that Tommy eats ... 2 * x
y ... the total number of pieces of fruit the monkey eats

The equation would be as follows: <span>y = 4 + 2 * x.</span>

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3 years ago

Find the solution of the differential equation that satisfies the given initial condition. du dt = 2t + sec2(t) 2u , u(0) = â2

serg [7]

It looks like the equation is

$\dfrac{du}{dt} = 2t + \dfrac12 \sec^2(t) u$

with initial value $u(0) = \frac\pi2$ .

Rearrange the equation to

$\dfrac{du}{dt} - \dfrac12 \sec^2(t) u = 2t$

Multiply both sides by the integrating factor

$\displaystyle \mu = \exp\left( \int -\frac12 \sec^2(t)\,dt\right) = \exp\left(-\frac12\tan(t)\right)$

and solve for $u$ .

$\implies e^{-\frac12 \tan(t)} \dfrac{du}{dt} - \dfrac12 \sec^2(t) e^{-\frac12 \tan(t)} u = 2t e^{-\frac12 \tan(t)}$

$\implies \dfrac{d}{dt}\left[e^{-\frac12 \tan(t)} u\right] = 2t e^{-\frac12 \tan(t)}$

By the fundamental theorem of calculus, integrating both sides yields

$e^{-\frac12\tan(t)} u = e^{-\frac12\tan(t)} u \bigg|_{t=0} + \displaystyle \int_{\xi=0}^{\xi=t} 2\xi e^{-\frac12 \tan(\xi)} \, d\xi$

$\implies e^{-\frac12\tan(t)} u = 1\times\dfrac\pi2 + \displaystyle \int_{0}^{t} 2\xi e^{-\frac12 \tan(\xi)} \, d\xi$

$\implies \boxed{\displaystyle u = \frac\pi2 e^{\frac12\tan(t)} + 2e^{\frac12\tan(t)} \int_0^t \xi e^{-\frac12 \tan(\xi)} \, d\xi}$

8 0

2 years ago