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forsale [732]
2 years ago
8

Ravi is putting money into a checking account. Let y represent the total amount of money in the account (in dollars). Let x repr

esent the number of weeks Ravi has been adding money. Suppose that x and y are related by the equation
y=550+40x
Answer the questions below.
Note that a change can be an increase or a decrease.
For an increase, use a positive number. For a decrease, use a negative number.
What is the change per week in the amount of money in the account?

What was the starting amount of money in the account?
Mathematics
1 answer:
nexus9112 [7]2 years ago
8 0

Answer:

1. The change per week is $40 as it is the coefficient.

2. The starting amount is $550 as it is the constant.

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Answer:

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Step-by-step explanation:

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3 years ago
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Jennifer is saving money to buy a bike. The bike costs $246. She has $138 saved, and each week she adds $18 to her savings.
Brrunno [24]

Answer: 8 weeks

explanation: 125 + 15x = 245

You then have to subtract 125 from both sides so we can isolate our variable which will give us 15x = 120 . Divide 15 from both sides : 15x/15 = 120/15 which will give us x = 8.

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3 years ago
Name a number that is an integer, but not whole number.
tekilochka [14]

Answer:

-1

Step-by-step explanation:

All negative integers are not whole numbers

4 0
2 years ago
Given the equation (x+a)^2(x-2)=x^3+bx^2+12x-72 find a and b
GaryK [48]
Isolate the variable by dividing each side by factors that don't contain the variable.

a=-  \frac{ x^{2}-  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,-  \frac{ x^{2}+  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

Solve for b by simplifying both sides of the equation then isolating the variabel.

b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

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7 0
3 years ago
Can anyone help me solve this
yawa3891 [41]

Answer:

a. $45.54; b. $51.42; c. See below

Step-by-step explanation:

a. 193 min

        Service charge = $40.00

1st 100 min @ 0.021 =      2.10

Next 93 min @0.037 = <u>    3.44 </u>

                        Total =  $45.54

b. 317 min

          Service charge = $40.00

  1st 100 min @ 0.021 =      2.10

2nd 100 min @ 0.037 =     3.70

        117 min @ 0.048 =   <u>   5.62</u>

                          Total =   $51.42

c. Piecewise function

The charge is  

  • $40.00 + 0.021t               if t ≤ 100
  • $42.10 + 0.037(t - 100)    if 100 < t ≤ 200
  • $45.80 + 0.048 (t - 200) if t > 200

which we can write like this:

f(t) =\begin{cases}40.00 + 0.021t & t \leq 100\\42.10 + 0.037(t-100) & 100 < t \leq200\\45.80 + 0.048(t-200) & t > 200\end{cases}

5 0
2 years ago
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