A 4x25=100 10x10=100 making 100 a common multiple of 4 and 10.
Answer:
The answer is the first choice, that the outcomes (getting a 2, 4, or 6 or getting a 1, 3, or 5) are equally likely because the frequencies are close.
Step-by-step explanation:
The second choice isn't true because there isn't a lot of variation. If there was, this would mean they aren't equally likely.
The third choice isn't true because it doesn't make a statement about why the odd/even identity of the sets should affect the likelihood. (Besides, we know they are equally likely.)
The fourth choice isn't true because there is not a lot of difference in the relative frequency.
please give me brainliest
Answer:
the one on the upper left with the triangular form
Step-by-step explanation:
all the others only represent one of the possibilities
Answer:
310.1
Step-by-step explanation:
Use the distance formula:
Simplify inside the parentheses
Simplify exponents
Simplify by adding
Simplify
Done. B-)
Answer:
The Answer is 0,133484. The same number as 
or 
Step-by-step explanation:
If the probability of an event occurring is <em>p</em>, then the probability of an event not occurring is <em>1-p</em>. Therefore if Lester plays one number, then the probability of that number not winning is 1-
or 1-0.25, which is 
or 0.75
Two or more events are independent if the occurrence of one does not affect the probability of occurrence of the other. In Lester's game, the probability of a number winning or not winning does not affect the probability of the same number winning or not winning in the next game.
In order to find the probability of several events occurring in succession, we multiply the probabilities of the individual events.
Therefore if Lester plays one number seven times, the probability that all seven bets lose are or
