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Liono4ka [1.6K]
3 years ago
6

Jerry jogs the same round trip path everyday. He jogs 0.7 miles to the park and then 0.5 miles from the park to the playground.

After getting a drink at the playground, he then jogs back from the playground to his house. He jogs from the playground to the bridge 0.3 miles and then 0.9 miles from the bridge to his house. When Jerry completes his jog, how many miles is he from his house?
Mathematics
2 answers:
Mila [183]3 years ago
6 0
Is this a trick question, i assume you just add all the number getting 2.4 miles or he is 0 miles away from his house when he completes his jog

Verizon [17]3 years ago
5 0

Answer:

He will be 0 miles from his house.

Step-by-step explanation:

Since, he jogs the same round trip path.

Thus,

\text{His final distance from his house }=d_1-d_2

Where, d_1 = The distance he covered in first trip (towards playground)  

d_2 = The distance he covered in second trip (towards house),

In his first trip,

He covered 0.7 miles to the park and then 0.5 miles from the park to the playground.

d_1 = 0.7 + 0.5 = 1.2\text{ miles},

In his second trip,

He covered 0.3 miles to the bridge and then 0.9 miles from the bridge to his house

d_2 = 0.3 + 0.9 = 1.2\text{ miles},

\text{His final distance from his house }=1.2-1.2=0\text{ miles}

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The expression which is equivalent to the given expression as in the task content is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.

<h3>What is the expression which is equivalent to the given expression?</h3>

According to the task content, it follows that the expression given is;

(1.5⁵/0.7⁴)³

= 1.5^(3×5) /0.7^(4×3)

= 1.5¹⁵/0.7¹².

Hence, the expression which is equivalent is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.

Read more on exponents;

brainly.com/question/847241

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A rectangular parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 yd.² find the l
ArbitrLikvidat [17]

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

<h2>mark me brainlist</h2>
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2 years ago
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