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3 years ago

Help me with this please!!!!!!

Mathematics

1 answer:

castortr0y [4]3 years ago

4 0

Answer:

$\huge\mathcal\red{here's \: your \: solution..} \\ \\ \cos = base \div hypotenuse \: \\ \\ \cos(60) = 1 \div 2 \\ \\ \cos = a \div 14 \\ \\ a \div 14 = 1 \div 2 \\ \\ a = 14 \div2 \\ \\ a = 7 \: cm \\ \\ \huge\mathfrak\green{hope \: it \: helps..}$

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(24x3 − 14x2 + 20x + 6) ÷ (4x2 − 3x + 5) = Q + R 4x2 − 3x + 5

riadik2000 [5.3K]

Answer:

Q= 6x+1

R= -7x+1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Mark has 17 coins that are dimes and quarters. The total value of the coins is $2.45. How many dimes does mark have?

seropon [69]

Answer: 12 dimes and 5 quarters

Step-by-step explanation: Let's start this problem by setting up a chart so we can organize our information that we're given in this problem.

Down the left side, we'll have our different types of coins. In this case dimes and quarters. Across the top we'll have our formula which is shown below.

Number of coins · value of each coin = total value

Now let's fill out our chart.

For number of dimes and quarters, we know that mark has a total of 17 dimes and quarters but we don't know how many of each he has. In fact, that's what the problem is asking.

So if we represent our number of dimes as x, we can call our number of quarters 17 - x.

The value of each dime is 10¢ and the value of each quarter is 25¢.

Our total value based on our formula is going to come from the first column times the second column. So the total value of our dimes is x times 10 or 10x and the total value of our quarters is 17 - x times 25 or 25 (17 - x).

Our goal in this problem will be to find x because x represents our number of dimes and the problem asks how many dimes does he have. If we know the number of dimes, we can easily find the number of dimes and we'll have our answer. However, we need an equation in order to find x.

It's important to understand that he information in this equation will always come from the last column of your chart, the total value column. So what do we know about the total value of our dimes and the total value of our quarters?

Well we know that the total value of all of our coins is $2.45. So if we add the total value of our dimes + the total value of our quarters, that should equal $2.45. So below the chart I added an additional box and I put 245 in it. Notice that I wrote 245 in terms of cents because our value of dimes and value of quarters is also written in terms of cents and we need to be constient.

So here's our equation.

10x + 25 (17 - x) = 245.

If we solve this, we get x = 12.

Going back up into our chart, remember that x represents our number of dimes so Mark has 12 dimes. To get his number of quarters, we take 17 - x which is 17 - 12 or 5 quarters and that's our answer.

I have also attached the chart that I have made below.

7 0

3 years ago

How do I solve this? x/3 + x^2 + 2x^2 - x/3

Anna11 [10]

Answer:

3x²

Step-by-step explanation:

$\frac{x}{3} + x^{2} +2x^{2} -\frac{x}{3}$ =

$x^{2} +2x^{2}$ =

$3x^{2}$

3 0

2 years ago

Easy 100 points, plz answer ASP! Please include an explanation!!

valina [46]

Answer:

The third option

Step-by-step explanation:

the most reasonable

6 0

3 years ago

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Suppose you hit a fly ball with an initial upward velocity of 20 feet per second. Which of the following equations would be a re

baherus [9]

A=g≈-32

v=⌠a dt since a≈-32

v=-32t+C, where C is the initial velocity, which we are told is 20 ft/s

v=-32t+20

h=⌠v dt

h=-32t^2/2+20t+C, where C is the initial height, so what is a reasonable initial height? How about 3 ft since we are swinging a bat around maybe our waist level... maybe :P

h=-16t^2+20t+3

Your choices may have made a different assumption about the initial height of course but you did not show your choices, but certainly it will be:

h(t)=-16t^2+20t+hi, where hi is the initial height in feet.

This of course ignores air resistance and flight dynamics of a spinning ball with seams, which will make a significant difference in real life :)

3 0

3 years ago

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