Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or
ft
=
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
=
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k(
)
k = 18
Work done (W) to stretch the spring by
ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9(
)²
= 7.56 lb-ft
money >= jeans + tshirts
65 >= 29 + 9* number of shirts
subtract 29 from each side
36> =9 *number of shirts
divide by 9 on each side
4 > =number of shirts
He can buy 4 or less shirts
Choice A
The first one is A and the second one is B, hope this helps!!
Answer: 3
Step-by-step explanation: Because, 1/2=2/4=3/6=4/8=5/10=6/12 are all the same. You can test is out by simply factoring out the biggest factor on both sides. For example, 2/4 can be simplified to 1/2, because 2/4=(2/2)/(4/2) you can divide both sides by two. Hope this helps, <3!
Step-by-step explanation:
6 times7-3^2 times 9+4^3=
(6*(7-3^2))*(9+4^3) =
(6(7-9)) *(9+64) =
(6*-2) (73) =
-12*73