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Lostsunrise [7]
3 years ago
12

Write 2 different addition equations that have 12 as a solution

Mathematics
1 answer:
pochemuha3 years ago
7 0

Answer:

6+6=12

10+2=12

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what is the difference between the surface areas of the Pyramid of Khafre and the Pyramid of Menkaure?
Svet_ta [14]
What do you think it is????
4 0
3 years ago
What is the slope of a line perpendicular to the line y = −14x – 1?
mash [69]

Answer:

<h2>         m = ¹/₁₄</h2>

Step-by-step explanation:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y = -14x - 1   ⇒   m₁ = -14

-14×m₂ = -1        ⇒    m₂ = ¹/₁₄

So, the slope of a line perpendicular to the line y = -14x - 1 is m = ¹/₁₄

5 0
3 years ago
I WILL MARK BRAINLIEST!!! 25 POINTS!!! Select ALL of the correct systems of equations.
choli [55]
The 3rd and 5th systems of equations are the answer.

Point A is at (3,-1), so all you do is input 3 for x and -1 for y into all the equations. For the systems to work, both equations must work with (3,-1).

Only the third and fifth boxes work.
8 0
4 years ago
Sharon uses 6.3 pints of blue paint and white paint to paint her bedroom walls. 4 5 of this amount is blue paint, and the rest i
Y_Kistochka [10]

Given:

Sharon uses 6.3 pints of blue paint and white paint to paint her bedroom walls.

\dfrac{4}{5}th of this amount is blue paint and the rest is white paint.

To find:

The pints of white paint did she use to paint her bedroom walls.

Solution:

We have,

Total paint used = 6.3 pints

Blue paint = \dfrac{4}{5}th of total paint used

                 = \dfrac{4}{5}\times 6.3

                 = 5.04

White paint = Total paint used - Blue paint

                   = 6.3-5.04

                   = 1.26

Therefore, Sharon uses 1.26 pints of white paint to paint her bedroom walls.

5 0
3 years ago
Two certificates of deposit pay interest that differ by 3%. Money invested for one year in the first CD earns $240 interest. The
Soloha48 [4]

a = interest rate of first CD

b = interest rate of second CD

and again, let's say the principal invested in each is $X.

\bf a-b=3\qquad \implies \qquad \boxed{b}=3+a~\hfill \begin{cases} \left( \frac{a}{100} \right)X=240\\\\ \left( \frac{b}{100} \right)X=360 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \left( \cfrac{a}{100} \right)X=240\implies X=\cfrac{240}{~~\frac{a}{100}~~}\implies X=\cfrac{24000}{a} \\\\\\ \left( \cfrac{b}{100} \right)X=360\implies X=\cfrac{360}{~~\frac{b}{100}~~}\implies X=\cfrac{36000}{b} \\\\[-0.35em] ~\dotfill\\\\

\bf X=X\qquad thus\qquad \implies \cfrac{24000}{a}=\cfrac{36000}{b}\implies \cfrac{24000}{a}=\cfrac{36000}{\boxed{3+a}} \\\\\\ (3+a)24000=36000a\implies \cfrac{3+a}{a}=\cfrac{36000}{24000}\implies \cfrac{3-a}{a}=\cfrac{3}{2} \\\\\\ 6-2a=3a\implies 6=5a\implies \cfrac{6}{5}=a\implies 1\frac{1}{5}=a\implies \blacktriangleright 1.2 = x\blacktriangleleft

\bf \stackrel{\textit{since we know that}}{b=3+a}\implies b=3+\cfrac{6}{5}\implies b=\cfrac{21}{5}\implies b=4\frac{1}{5}\implies \blacktriangleright b=4.2 \blacktriangleleft

3 0
3 years ago
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