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2 years ago

Gail collects trading cards. Her favorites are baseball and football cards. For

Mathematics

2 answers:

mamaluj [8]2 years ago

8 0

I think it’s c but don’t go with me see if others answer with a different answer :)

EleoNora [17]2 years ago

5 0

Step-by-step explanation:

its ratio so it has to be A

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Write an expression that represent the sum of r and 7

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"The sum of r and 7" can be represented as r + 7

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3 years ago

Which of the following is NOT a reason for forced migration?

swat32

Chance for better wages

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3 years ago

Read 2 more answers

if the area of a square is 144 feet and the perimeter of the triangle is 28 feet, what is the perimeter of the room's floor?

FinnZ [79.3K]

Answer:

$52+12\pi$

Step-by-step explanation:

The diagram for the question is attached below

perimeter of the triangle is 28 feet

area of a square is 144 feet

Area of the square is side^2

$side ^2= 144$

take square root on both sides

side = 12

side of the square = 12

side is the diameter of the semicircle

Diameter = 12 , so radius = 12 divide 2 = 6

circumference of semicircle = $2\pi r=2\pi (6)=12\pi$

one side of the rectangle is calculated in the perimeter of triangle and other side is calculated using circumference

perimeter of other two side = 2(12)= 24

Total perimeter = $28+24+12\pi =52+12\pi$

4 0

3 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .