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Roman55 [17]
3 years ago
10

If f(x) = –x2 + 3x + 5 and g(x) = x2 + 2x, which graph shows the graph of (f + g)(x)?

Mathematics
1 answer:
Dmitry [639]3 years ago
5 0

Answer:

The answer is

<h3>the last graph</h3>

Step-by-step explanation:

To find the graph which shows (f + g)(x) we must first find (f + g)(x)

That's

f(x) = - x² + 3x + 5

g(x) = x² + 2x

To find (f + g)(x) add g(x) to f(x)

That's

(f + g)(x) = -x² + 3x + 5 + x² + 2x

Group like terms

(f + g)(x) = - x² + x² + 3x + 2x + 5

We have (f + g)(x) as

(f + g)(x) = 5x + 5

Since (f + g)(x) is linear the graph which shows (f + g)(x) is <u>the last graph</u>

Hope this helps you

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Given the function f(x) =
jenyasd209 [6]

Answer:

The value of f(1) is smaller than the value of f(3)

Step-by-step explanation:

<u><em>The correct question is</em></u>

Given the function f(x) = 2x^2 + 3x + 10, find f(1) and f(3). Choose the statement that is true concerning these two values.

The value of f(1) is the same as the value of f(3).

The value of f(1) cannot be compared to the value of f(3).

The value of f(1) is larger than the value of f(3).

The value of f(1) is smaller than the value of f(3)

we have

f(x)=2x^{2}+3x+10

step 1

Find out the value of f(1)

substitute the value of x=1 in the function f(x)

so

For x=1

f(1)=2(1)^{2}+3(1)+10

f(1)=15

step 2

Find out the value of f(3)

substitute the value of x=3 in the function f(x)

so

For x=3

f(3)=2(3)^{2}+3(3)+10

f(3)=37

step 3

Compare the values

37> 15

so

f(3) > f(1)

or

f(1) < f(3)

therefore

The value of f(1) is smaller than the value of f(3)

8 0
3 years ago
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