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Reil [10]
3 years ago
15

What percent of 56 is 48?​

Mathematics
1 answer:
Vinvika [58]3 years ago
4 0
Take 56 divide by 48
We would get 1.16666 repeating
Multiple the decimal by 100 to find the percentage
1.166 x 100= 116.6%
56 is 116.6% of 48.
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Stefan sells Jin a bicycle for $163 and a helmet for $17. The total cost for Jin is 150% of what Stefan spent originally to buy
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Step-by-step explanation:

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Please help me to solve this ​
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let a function F:A➡️B be defined by f(x)=x+1÷2x-1 with A={-1,0,1,2,3,4} and B= {-1,0,4/5,5/7,1,2,3,}.Find the range of f. plzzzz
lidiya [134]

Answer:

Range: {-1, 0, 5/7, 4/5, 1, 2}

Step-by-step explanation:

We know that:

f(x) = (x + 1)/(2x - 1)

And:

f: A ⇒ B

where:

A={-1,0,1,2,3,4}

B= {-1,0,4/5,5/7,1,2,3,}

We want to find the range of f(x).

The range of f(x) will be the set of the outputs of f(x) (and because f goes from A to B, we will only take the outputs that belong to B).

Then we only need to evaluate all the values of A in f(x), and see if the output belongs to B.

we have:

f(x) = (x + 1)/(2x - 1)

f(-1) = (-1 + 1)/(2*-1 - 1) = 0   (this does belong to B)

f(0) = (0 + 1)/(2*0 - 1) = -1  (this does belong to B)

f(1) = (1 + 1)/(2*1 - 1) = 2  (this does belong to B)

f(2) = (2 + 1)/(2*2 - 1) = 1 (this does belong to B)

f(3) = (3 + 1)/(2*3 - 1) = 4/5  (this does belong to B)

f(4) = (4 + 1)/(2*4 - 1) = 5/7  (this does belong to B)

So the range of f(x) is the set with all these outputs, which is:

Range: {-1, 0, 5/7, 4/5, 1, 2}

5 0
3 years ago
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
4 years ago
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