No because he will be $3.00 short.
So it is $0.75 a bottle. So then you multiply $0.75 by 20. You get $15.00
So David will not have enough in his wallet.
complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
The answer is c all the others are 1/3 fractions
Answer:
z1 + z2 = 3
Step-by-step explanation:
Since we are given z1 = 2 + √(3)i and z2 = 1 – √(3)i. The sum of z1 + z2 would be:
(2 + √(3)i) + (1 – √(3)i) = 2 + √(3)i + 1 – √(3)i = 2 + 1 + √(3)i – √(3)i = 3
Hence, z1 + z2 = 3.
All you have to do is subtract 3/8 from 7 which would give you 9 and 1/3
