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12345 [234]
3 years ago
8

A negative number raised to an odd power ______ negative

Mathematics
2 answers:
Fiesta28 [93]3 years ago
3 0
A negative number raised to an odd power IS negative
love history [14]3 years ago
3 0

Answer:

A negative number raised to an odd power is always negative.

Step-by-step explanation:

To complete the statement - A negative number raised to an odd power ______ negative.

Solution :

We know that,

A negative number raised to an odd power is always negative.

1) When a negative number is raised to an even power, the pairs of negatives will cancel out.

For example - (-1)^2=(-1)\times (-1)=1

2) When it is raised to an odd power, after pairs of the negative sign have canceled each other out, there will still be one minus sign left unpaired, which will not cancel out.

For example - (-1)^3=(-1)\times (-1)\times (-1)=1\times (-1)=-1

Therefore, The required blank is 'always'.

You might be interested in
-. A 6-foot-tall man is standing 50 feet from a flagpole. When he looks at the top of the flagpole,
taurus [48]

Answer:

The height of the flagpole is 46 feet

Step-by-step explanation:

First we find the ratio to connect the variables

Tan(∅) = opposite/adjacent

Plug in the Variables

Tan(39) = x/50

Solve for x

50*tan(39) = x

x = 40.48

Don't forget to include the man's height

40.48 + 6 = 46.48

7 0
3 years ago
Just need the answer. it was "Check all that apply." at the end.
lianna [129]

Billy, let's recall what a linear pair of angles is:

• They are formed when two lines intersect.

,

• Two angles are said to be linear if they are adjacent angles formed by two intersecting lines.

,

• The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

Upon saying that we have that:

• CAD and DAE are linear pairs

,

• CAD and CAB are linear pairs

,

• DAE and BAE are linear pairs

,

• DAE and DAC are linear pairs

Now, you are ready to select all the options that actually apply.

3 0
1 year ago
Please Help! This is a trigonometry question.
liraira [26]
\large\begin{array}{l} \textsf{From the picture, we get}\\\\ \mathsf{tan\,\theta=\dfrac{2}{3}}\\\\ \mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{2}{3}}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\qquad\mathsf{(i)} \end{array}


\large\begin{array}{l} \textsf{Square both sides of \mathsf{(i)} above:}\\\\ \mathsf{(3\,sin\,\theta)^2=(2\,cos\,\theta)^2}\\\\ \mathsf{9\,sin^2\,\theta=4\,cos^2\,\theta}\qquad\quad\textsf{(but }\mathsf{cos^2\theta=1-sin^2\,\theta}\textsf{)}\\\\ \mathsf{9\,sin^2\,\theta=4\cdot (1-sin^2\,\theta)}\\\\ \mathsf{9\,sin^2\,\theta=4-4\,sin^2\,\theta}\\\\ \mathsf{9\,sin^2\,\theta+4\,sin^2\,\theta=4} \end{array}

\large\begin{array}{l} \mathsf{13\,sin^2\,\theta=4}\\\\ \mathsf{sin^2\,\theta=\dfrac{4}{13}}\\\\ \mathsf{sin\,\theta=\sqrt{\dfrac{4}{13}}}\\\\ \textsf{(we must take the positive square root, because }\theta \textsf{ is an}\\\textsf{acute angle, so its sine is positive)}\\\\ \mathsf{sin\,\theta=\dfrac{2}{\sqrt{13}}} \end{array}

________


\large\begin{array}{l} \textsf{From (i), we find the value of }\mathsf{cos\,\theta:}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{2}\,sin\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\diagup\!\!\!\! 2}\cdot \dfrac{\diagup\!\!\!\! 2}{\sqrt{13}}}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\sqrt{13}}}\\\\ \end{array}

________


\large\begin{array}{l} \textsf{Since sine and cosecant functions are reciprocal, we have}\\\\ \mathsf{sin\,2\theta\cdot csc\,2\theta=1}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{sin\,2\theta}\qquad\quad\textsf{(but }}\mathsf{sin\,2\theta=2\,sin\,\theta\,cos\,\theta}\textsf{)}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\,sin\,\theta\,cos\,\theta}}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\cdot \frac{2}{\sqrt{13}}\cdot \frac{3}{\sqrt{13}}}} \end{array}

\large\begin{array}{l} \mathsf{csc\,2\theta=\dfrac{~~~~1~~~~}{\frac{2\cdot 2\cdot 3}{(\sqrt{13})^2}}}\\\\ \mathsf{csc\,2\theta=\dfrac{~~1~~}{\frac{12}{13}}}\\\\ \boxed{\begin{array}{c}\mathsf{csc\,2\theta=\dfrac{13}{12}} \end{array}}\qquad\checkmark \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2150237


\large\textsf{I hope it helps.}


Tags: <em>trigonometry trig function cosecant csc double angle identity geometry</em>

</span>
8 0
3 years ago
Which of the following are equivalent ratios?<br><br> 15 to 20<br> 6 to 8<br> 8 to 12<br> 9 to 12
I am Lyosha [343]
So yuo simplyfly

15:20=3:4

6:8=3:4

8:12=2:3

9:12=3:4

so your answer is not c
3 0
3 years ago
Read 2 more answers
Find the coordinates of the midpoint of the segment whose endpoints are h(6,4) and k(2,8)
ozzi

Answer:

(4,6)

Step-by-step explanation:

we know that

The formula to calculate the coordinates of the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have that

The coordinates of hk

h(6,4), k(2,8)

substitute in the formula to calculate the midpoint

M(\frac{6+2}{2},\frac{4+8}{2})

M(\frac{8}{2},\frac{12}{2})

M(4,6)

7 0
3 years ago
Read 2 more answers
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