1) Speed = distance / time
s = 60 / 2
s = 30 km/h
In short, Your Answer would be Option B
2) Speed = distance / time
s = 25/4
s = 6.25 km/h
In short, Your Answer would be Option B
[ Direction not needed as it is speed not velocity ]
Hope this helps!
<u>Answer:</u>
Although statements are not given in the question, we could make the most possible deduction as follows:
The allele for purple flowers is dominant whereas allele for white flowers is recessive.
<u>Explanation:</u>
According to the question,
- Purple flower plant was crossed with white flower plant.
- All offsprings have purple flowers.
Here we have one possibility that both parents were homozygous but in their own traits. <u>Purple flower</u> plants were "PP" and white <u>flower plants</u> were "pp" So, the <u>first progeny</u> (direct offsprings) would have "Pp". So, as per considerations, purple is dominant allele which will mask the recessive allele thus defining the color of all offsprings as purple. However, further cross of their generation will definitely end up into purple and white flowers (3:1) but this condition is not mentioned in the statement.
The “bases” of RNA differ from those of DNA in that thymine (T) is replaced by uracil (U) in RNA. ... In DNA/RNA base pairing, adenine (A) pairs with uracil (U), and cytosine (C) pairs with guanine (G).
<span>The propositions are:
a. forms glucose from </span><span>noncarbohydrates
b. does all of these
c. destroys damaged red blood cells
d. stores vitamin D
e. forms urea
The right answer is: B. </span>does all of these
*The liver plays a role in the metabolism of carbohydrates:- gluconeogenesis (manufacture of a new glucose molecule from a non-carbohydrate molecule);- glycogenolysis (release of glucose from glycogen) under the effect of glucagon;- gluconeogenesis (storage of glucose in the form of glycogen) under the effect of insulin
*It stores fat-soluble vitamins (A, D, K and E) and glycogen.*It converts ammonia to urea (detoxification)<span>*It recycles substances from the senescent red blood cells.</span>
