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Ghella [55]
3 years ago
14

At a carnival game, you randomly throw two darts at the board and break two balloons. What is the probability that both the ball

oons you break are purple? There are 15 balloons total. 4 are purple.
Mathematics
1 answer:
Amanda [17]3 years ago
6 0
4/15 of the balloons are purple. You have two darts. There are 105 combinations of hitting two balloons out of the 15. There are 6 combinations of purple balloons to be hit. This (Purple combinations over total combinations) is your probability. 6/105 simplified to 2/35 or 2:35
So your chance of picking the purple balloons, both purple, out is 2 in 35 or 2/35
Brainliest?
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There are 221 students on a field trip.
DerKrebs [107]

The number of students in each bus is an illustration of a linear function

The equation that represents the number of students in each bus is: \mathbf{s= \frac{216}{6}}

The number of students is given as:

\mathbf{Students = 221}

Subtract 5 from the equation, to get the number of students that fill the bus

\mathbf{b= 221 - 5}

\mathbf{b= 216}

Divide both sides by 6 to get the number of students in a bus

\mathbf{\frac{b}{6}= \frac{216}{6}}

Represent students in the bus with s

\mathbf{s= \frac{216}{6}}

Hence, the equation that represents the number of students in each bus is: \mathbf{s= \frac{216}{6}}

Read more about linear equations at:

brainly.com/question/11897796

3 0
3 years ago
Which is the equation for line AB
miskamm [114]

The equation for line AB would be x = -5 but It looks like it is asking for line AD.

The equation of line AD can be written in slope-intercept form y=mx+b, m being the slope and b the y intercept.

The y intercept would be point D since it is on the y axis. The y intercept would be (0,6) or 6 in the equation.

The slope can be calculated by the slope formula which is m = y2-y1/x2-x1

For the slope form we have to plug in both points A and D

6-1 over 0+5 y x

The slope is y/x and 6-1=5 and 0+5=5. This means that the slope is 5/5 or just 1. Now that we have the slope, we can form the equation y=x+6.

Since we have to turn it into standard form, we move x to the other side of the equation using Subtraction property of equality to get as the final answer

-x+y=6

8 0
3 years ago
Determine whether or not f is a conservative vector field. If it is, find a function f such that f = ∇f. (if the vector field is
Likurg_2 [28]

A function assigns the values. The function f = xy²-2x² satisfies a conservative vector field F = ∇f.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

Given F(x,y) = (y² - 4x) i + 2xy j, and it is needed to be known that,

f_x(x,y)=y^2-4x\\f_y(x,y) = 2xy

Let's look for a primitive of y²-4x with regard to x. Because we regard y (and y²) as constants, a primitive of y² is xy², just as a primitive of k is xk (because we treat y² as a constant). Because a primitive of x equals x²/2, a primitive of 4x is 2x². As a result, a primitive of y²-4x is xy²-2x². We can get any other primitive by adding constants, but because we considered y as a constant, we have that.

f(x,y) = xy²-2x²+c(y)

where c(y) only depends on y (thus, it is constant respect with x).

To learn more about c(y), we shall deduce the formula in terms of y.

2xy=f_y(x,y)

      =\dfrac{d}{dy}(xy^2-2x^2+c(y))\\\\=2xy-0+\dfrac{d}{dy}c(y)\\\\=2xy+\dfrac{d}{dy}c(y)

Thus, d/dy is constant. We can take f(x,y)=xy²-2x². This function f satisfies that  F = ∇f.

Learn more about Function:

brainly.com/question/5245372

#SPJ4

3 0
2 years ago
What is the range of this function?
stiv31 [10]

Answer:

c

Step-by-step explanation:

outputs are on the right, which are the y-values.

3 0
4 years ago
Point A is on a number line halfway between -20 and -4. Point B is halfway between point A and 0. What integer is represented by
wariber [46]
I can't really make a number line here but
between -20 and -4, just make a number line and count and you should reach -12. Because they are |8| away from -12.

If point A is -8, them between -8 and 0 is -4.
7 0
4 years ago
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