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quester [9]
3 years ago
12

Find the value of x.

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0
I got the same answer as the person above me ^
Brrunno [24]3 years ago
4 0

Answer:

x = 6

Step-by-step explanation:

cos 60° = JK/JL

cos 60° = 7 / (3x-4)

(1/2) = 7 / (3x-4)

(1/2) = 7 / (3x-4)

(3x-4) = (2)(7)

3x-4 = 14

3x = 14+4

3x = 18

x = 18/3

x = 6

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Pls help will mark brainliest to first answer
Serga [27]

Answer:

A. pi(6)^2* 8

Step-by-step explanation:

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3 years ago
How do you find the missing angle of a triangle when all other angles are there?
olya-2409 [2.1K]
All angles in a triangle add up to 180 degrees. So, if you are missing an angle, add up the degrees of the angles present and subtract that from 180. That will be the value of the missing angle in degrees.
7 0
3 years ago
(x2 - x - 2) ÷ (x - 2)
kifflom [539]

Answer:

(x+1)

Step-by-step explanation:

(x^2-x-2)/(x-2)=(x+1)

Because (x-2)(x+1)=x^2-2x+x-2=x^2-x-2.

7 0
3 years ago
Read 2 more answers
Bin $A$ has one white ball and four black balls. Bin $B$ has three balls labeled $\$1$ and one ball labeled $\$7$. Bin $W$ has f
nydimaria [60]

Answer:

$20

Step-by-step explanation:

Bin A:                             Bin B:                  Bin W:

white ball: 20%              $1: 75%                $8: 5/6

black ball: 80%              $7: 25%               $500: 1/6

first we can calculate the expected return of bins B and W:

expected return if the ball is black = ($1 x 75%) + ($7 x 25%) = $2.50

expected return if the ball is white = ($8 x 5/6) + ($500 x 1/6) = $90

expected return of the game = (expected return of a black ball x probability of choosing a black ball) + (expected return of a white ball x probability of choosing a white ball) =($2.50 x 80%) + ($90 x 20%) = $2 + $18 = $20

3 0
3 years ago
Read 2 more answers
Find f(g(x)). State the domain of the composite function.<br> f(x) = 3x-2/x+1<br> g(x) = x+5/2x-3
AnnyKZ [126]

Answer:

ℝ - {(-2/3),(3/2)}

Step-by-step explanation:

We want the domain of f(g(x)). So, firstly, we have to find the domain for g(x) and, then, for f(g(x)).

- Domain of g(x): Since the expression is a fracion, we must exclude the values of x that make null the denominator. Hence,

g(x)=\dfrac{x+5}{2x-3}\Longrightarrow 2x-3\neq 0\iff \boxed{x\neq\dfrac{3}{2}}

- Domain of f(g(x)): We'll find its expression:

f(x) = \dfrac{3x-2}{x+1}\\\\f(g(x)) = \dfrac{3g(x)-2}{g(x)+1}\\\\f(g(x)) = \dfrac{3\cdot\dfrac{x+5}{2x-3}-2}{\dfrac{x+5}{2x-3}+1}=\dfrac{~~~\dfrac{3(x+5)-2(2x-3)}{2x-3}~~~}{\dfrac{(x+5)+(2x-3)}{2x-3}}\\\\f(g(x)) =\dfrac{3(x+5)-2(2x-3)}{(x+5)+(2x-3)}=\dfrac{3x+15-4x+6}{x+5+2x-3}\\\\\boxed{f(g(x)) =\dfrac{21-x}{3x+2}}

Now, once again, we have to exclude the values of x that make the denominator equals to zero. Thus,

f(g(x)) =\dfrac{21-x}{3x+2}\Longrightarrow 3x+2\neq0\iff \boxed{x\neq-\dfrac{2}{3}}

Lastly, we may write the domanin of f(g(x)):

D(f(g(x)) = \left]-\infty,-\dfrac{2}{3}\right[\cup\left]-\dfrac{2}{3},\dfrac{3}{2}\right[\cup\left]\dfrac{3}{2},\infty\right[

or, just writing in a shorter way:

\boxed{D(f(g(x)) = \mathbb{R}-\left\{-\dfrac{2}{3},\dfrac{3}{2}\right\}}

7 0
3 years ago
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