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3 years ago

Helppppppp plsssssssss

Mathematics

2 answers:

wlad13 [49]3 years ago

8 0

It is 130
Use the abc-formula
a²+b²=c²
so: 120²+50²=c²
14.400+2.500=16900
c²=16900
$c = \sqrt{16900} = 130$

umka2103 [35]3 years ago

4 0

I'm not sure if I'm right but I got 170m

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Write a direct or inverse variation equation for each relation.

igor_vitrenko [27]

Answer:

6 it is 6

Step-by-step explanation:

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3 years ago

X+4/4=x/x-2 A:{-4,2} B:{-2,4} C:{}

Andreyy89

Answer:

The correct answer is B. {-2,4}

Step-by-step explanation:

Let's solve for x, this way:

x + 4/4 = x /x -2

(x + 4) * ((x - 2) = 4 * x

x² - 2x + 4x -8 = 4x

x² - 2x + 4x -8 - 4x = 0

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3 years ago

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pashok25 [27]

Step-by-step explanation:

[ Refer to the attachment ]

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3 years ago

A country is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30

kondaur [170]

Answer:

We conclude that speed is greater than 30 miles per hour.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 30 miles per hour

Sample mean, $\bar{x}$ = 35 miles per hour

Sample size, n = 15

Alpha, α = 0.01

Sample standard deviation, s = 4.7 miles per hour

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30\text{ miles per hour}\\H_A: \mu > 30\text{ miles per hour}$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{35 - 30}{\frac{4.7}{\sqrt{15}} } = 4.120$

Now, $t_{critical} \text{ at 0.01 level of significance, 14 degree of freedom } = 2.624$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis and conclude that speed is greater than 30 miles per hour.

We calculate the p-value.

P-value = 0.00052

Since p value is lower than the significance level, we reject the null hypothesis and accept the alternate hypothesis. We conclude that speed is greater than 30 miles per hour.

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3 years ago

A ship leaves port on a bearing of 34.0° and travels 10.4 miles. the ship then turns due east and travels 4.6 miles. how far is

maks197457 [2]

is a clockwise angle measured from due North. This is a problem, because all of the trigonometric functions are referenced to a counterclockwise angle measured from East.

A bearing of 34∘ corresponds to a trigonometric angle of θ1=90∘−34∘=56∘

The (x,y) values for the position of the ship after completing its first heading are:

x=(10.4mi)cos(56∘)
y=(10.4mi)sin(56∘)

The trigonometric angle for the second heading is θ2=90∘−90∘=0∘

The (x,y) values for the position of the ship after completing its second heading is:

x=(10.4mi)cos(56∘)+(4.6mi)cos(0∘)≈10.4mi
y=(10.4mi)sin(56∘)+(4.6mi)sin(0∘)≈8.6mi

The distance from port is:

d=√(10.4)2+(8.6)2≈13.5mi

Its trigonometric angle is:

θ=tan−1(yx)

θ=tan−1(8.610.4)

θ≈39.6∘

The bearing angle is:

θb=90∘−39.6∘=50.4∘

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4 years ago