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creativ13 [48]
3 years ago
12

Helppppppp plsssssssss

Mathematics
2 answers:
wlad13 [49]3 years ago
8 0
It is 130
Use the abc-formula
a²+b²=c²
so: 120²+50²=c²
14.400+2.500=16900
c²=16900
c =  \sqrt{16900}  = 130

umka2103 [35]3 years ago
4 0
I'm not sure if I'm right but I got 170m

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kodGreya [7K]
You mean, what is this number?

we can rephrase it like this: the sum of a number x and 8 is 15

which is:

x+8=15

we subtract 8 from both sides and we get
x=7

so the answer is 7.
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For the function f(x) = x + 5 , what is the order pair for the point on the graph when X=4w
pantera1 [17]
F(x) = x + 5;    x = 4w

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points C,D, and E are collinear on CE, and CD:DE = 3/5. C is located at (1,8), D is located at (4,5), and E is located at (x,y).
kap26 [50]

Answer:

The point E is located at (9,0)

x=9, y=0

Step-by-step explanation:

we have that

Points C,D, and E are collinear on CE

Point D is between point C and point E

we know that

CE=CD+DE -----> equation A (by addition segment postulate)

\frac{CD}{DE}=\frac{3}{5}

CD=\frac{3}{5}DE ------> equation B

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

<em>Find the distance CD   </em>

we have

C(1,8), D(4,5)

substitute in the formula

CD=\sqrt{(5-8)^{2}+(4-1)^{2}}

CD=\sqrt{(-3)^{2}+(3)^{2}}

CD=\sqrt{18}\ units

<em>Find the distance DE</em>

substitute the value of CD in the equation B and solve for DE

\sqrt{18}=\frac{3}{5}DE

DE=\frac{5\sqrt{18}}{3}\ units

<em>Find the distance CE</em>

CE=CD+DE

we have

DE=\frac{5\sqrt{18}}{3}\ units

CD=\sqrt{18}\ units

substitute the values in the equation A

CE=\sqrt{18}+\frac{5\sqrt{18}}{3}

CE=\frac{8\sqrt{18}}{3}

<em>Applying the formula of distance CE</em>

we have

CE=\frac{8\sqrt{18}}{3}

C(1,8), E(x,y)    

substitute in the formula of distance

\frac{8\sqrt{18}}{3}=\sqrt{(y-8)^{2}+(x-1)^{2}}

squared both sides

128=(y-8)^{2}+(x-1)^{2}  -----> equation C

<em>Applying the formula of distance DE</em>

we have

DE=\frac{5\sqrt{18}}{3}\ units

D(4,5), E(x,y)    

substitute in the formula of distance

\frac{5\sqrt{18}}{3}=\sqrt{(y-5)^{2}+(x-4)^{2}}

squared both sides

50=(y-5)^{2}+(x-4)^{2}  -----> equation D

we have the system

128=(y-8)^{2}+(x-1)^{2}  -----> equation C

50=(y-5)^{2}+(x-4)^{2}  -----> equation D

Solve the system by graphing

The intersection point both graphs is the solution of the system

The solution is the point (9,0)

therefore

The point E is located at (9,0)

see the attached figure to better understand the problem

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You are planning a 9 day trip to Texas. It will cost approximately $350 per day in
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Answer:

4 days in Houston and 5 days in Sand Antonio

Step-by-step explanation:

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