Answer:
See Below
Explanation:
Expected value is the sum of the products of the probability and payoff of each.
<u>Wager 1:</u>
probability of heads and tails, both is 0.5
Win = 440
Loose = 110
So,
Expected Value = 440(0.5) + (-110)(0.5) = 220 - 55 = $165
<u>Wager 2:</u>
Similar to wager 1
Win = 770
Loose = 220
So,
Expected value = 770(0.5) + (-220)(0.5) = 385 - 110 = $275
2nd wager is better, in this sense.
The answer would be between A and D.
Answer:
maintenance phase
Explanation:
Maintenance phase -
It refers to the phase of making the changes in the software , hardware and documentation to improve the operations effectively , is referred to as the maintenance phase .
The phase is important , as it enhances the efficiency and corrects the problem .
The company or the organisation tries to invest the maximum amount in the maintenance phase .
Hence , from the given statement of the question,
The correct option is maintenance phase .
Answer:
The graph has been attached.
Explanation:
a. Please see attached graph with the shaded budget set labelled A
b. Please see attached. Curve C; D and E are the indifference curves. The most suitable one would be D since it is on the budget curve. E is not maximum utility and C is unattainable given his budget of $20.
c. U (X,Y) = X + 2Y
At C, Utility = 10 + 2(10) = $30. That is above his budget
At D, Utility = 10 + 2(5) = $20. This is within his budget. – most utility.
At E, Utility = 5 + 2(5) = $15. This is below his budget.
The Indifference curve that gives most utility is D, where cheese is 10 and cocoa is 5 units.
Demand supply and market equilibrium will have many changes due to change in the quantity of a supplied product.