Answer:
x is greater than or equal to -7 but less than 9.
Step-by-step explanation:
Find the lowest and higest points on the graph.
Remember the domain is on the x - axis.
The lowest point on the graph is -7, but the dot is filled in so it must be equal to it.
The next step is that the graph is getting larger so it is greater than or equal to.
On the other side of the graph do the same but it is less than not equal because the dot is open.
Answer:
The equation is 
Step-by-step explanation:
The initial value or "b" is 2 and the slope is 
or just 2
Answer:
<em>1 ) Adjacent angles,</em>
<em>2 ) See solution below</em>
Step-by-step explanation:
Question 1. Provided ∠ 1 and ∠ 1 are near one another, they can be referred to as adjacent ∠s;
<em>Solution; Adjacent angles</em>
Question 2.
Angles 5, and 6 are consecutively near one another, and thus are adjacent angles,
Angles 5 and 9 are supplementary knowing that they lie on a straight angle, so that they can be best named a linear pair, provided there are only two of these angles,
Angles 5 and 8 are opposite to one another so that they are ≅, thus should be names as vertical angles
<em>Solution; </em>
Angle | Adjacent Angles | Linear Pair | Vertical angles
∠ 5, 6 | Check! | |
∠ 5, 9 | | Check! |
∠ 5, 8 | | | Check!
Answer:
Expected number of free throws in 60 attempts:
Best player = 48
2nd best player = 45
3rd best player = 42
Step-by-step explanation:
Solution:-
- The probability that best player makes free throw, p1 = 0.8
- The probability that second-best player makes free throw, p2 = 0.75
- The probability that third-best player makes free throw, p3 = 0.70
- Total number of attempts made in free throws, n = 60.
- The estimated number of free throws that any player makes is defined by:
E ( Xi ) = n*pi
Where, Xi = Player rank
pi = Player rank probability
- Expected value for best player making the free throws would be:
E (X1) = n*p1
= 60*0.8
= 48 free throws
- Expected value for second-best player making the free throws would be:
E (X2) = n*p2
= 60*0.75
= 45 free throws
- Expected value for third-best player making the free throws would be:
E (X3) = n*p3
= 60*0.70
= 42 free throws
