NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

Using the quadratic formula, the solution for our problem is

The rocket splashes after 26.845 seconds.
The maximum of this function happens at the root of the derivative. Differentiating our function, we have

The root is

Then, the maximum height is

1029.99 meters above sea level.
Answer:
They studied for a little more than an hour?
Step-by-step explanation:
7/12 of 60 Mins is 35 mins and 2/3 is 40 mins 40+35=75 mins
which is a little more than an hour, 15 mins more to be precise.
Answer:
m = 48
Step-by-step explanation:
6=m/8
Multiply each side by 8
6*8 = m/8 *8
48 = m
C=2x Pi x R so 2x3.14x17.5 = 109.9
The answer is actually 80 degrees, I just took the test.