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balandron [24]
3 years ago
14

Everbank Field, home of the Jacksonville Jaguars, is capable of seating 76,867 fans. The revenue for a particular game can be mo

deled as a function of the number of people in attendance, x. If each ticket costs $161, find the domain and range of this function.
Mathematics
1 answer:
k0ka [10]3 years ago
6 0
The total revenue for the event would the total amount earned from the tickets sold. So if x people attended the event, then there would be $(161x). We must keep in mind though the the maximum seating is 76 876. That means that the maximum revenue that can be earned must not exceed $(161)(76 867) = . Hence we have f(x) = 161x where 0 ≤ x ≤ 76867. From this, we can see that the domain is [0, 76867] while range is [0, 12375587]<span>.</span>
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Please explain how to do this
Nat2105 [25]

Answer:

61%

Step-by-step explanation:

Area of square:

=a²

=12²

=144

Area of two quarter circles:

=2(¼×π×r²)

=2(¼×π×6²)

=2×28.72

=56.55

Finding the percentage:

=(56. 55÷144)×100

=0.3937×100

=39.27

<u>subtract</u><u> </u><u>100</u><u>%</u><u> </u><u>by</u><u> </u><u>39.27</u><u>%</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>percentage</u><u> </u><u>of</u><u> </u><u>how</u><u> </u><u>much</u><u> </u><u>is</u><u> </u><u>shaded</u>

<u>=</u><u>100-39.27</u>

=60.73

=61 (rounded off to the nearest whole percent)

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3 years ago
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In a survey, 26 voters were asked their ages. The results are shown below. Given a lower class limit of 20 and a class width of
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Answer:

Waka Waka wa e e - queen shakira

7 0
3 years ago
Simplify the fraction 12 1/8
Pavlova-9 [17]
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3 years ago
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In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 3.0 m/s up a 22.0° inclined track
Aloiza [94]

Answer:

Approximately 0.31\; \rm m, assuming that g = 9.81\; \rm N \cdot kg^{-1}.

Step-by-step explanation:

Initial kinetic energy of the sled and its passenger:

\begin{aligned}\text{KE} &= \frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2} \times 14\; \rm kg \times (3.0\; \rm m\cdot s^{-1})^{2} \\ &= 63\; \rm J\end{aligned} .

Weight of the slide:

\begin{aligned}W &= m \cdot g \\ &= 14\; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \\ &\approx 137\; \rm N\end{aligned}.

Normal force between the sled and the slope:

\begin{aligned}F_{\rm N} &= W\cdot  \cos(22^{\circ}) \\ &\approx 137\; \rm N \times \cos(22^{\circ}) \\ &\approx 127\; \rm N\end{aligned}.

Calculate the kinetic friction between the sled and the slope:

\begin{aligned} f &= \mu_{k} \cdot F_{\rm N} \\ &\approx 0.20\times 127\; \rm N \\ &\approx 25.5\; \rm N\end{aligned}.

Assume that the sled and its passenger has reached a height of h meters relative to the base of the slope.

Gain in gravitational potential energy:

\begin{aligned}\text{GPE} &= m \cdot g \cdot (h\; {\rm m}) \\ &\approx 14\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times h\; {\rm m} \\ & \approx (137\, h)\; {\rm J} \end{aligned}.

Distance travelled along the slope:

\begin{aligned}x &= \frac{h}{\sin(22^{\circ})} \\ &\approx \frac{h\; \rm m}{0.375}\end{aligned}.

The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:

\begin{aligned} & - (-x)\, f \\ = \; & x \cdot f \\ \approx \; & \frac{h\; {\rm m}}{0.375}\times 25.5\; {\rm N} \\ \approx\; & (68.1\, h)\; {\rm J}\end{aligned}.

In other words, the sled and its passenger would have lost (approximately) ((137 + 68.1)\, h)\; {\rm J} of energy when it is at a height of h\; {\rm m}.

The initial amount of energy that the sled and its passenger possessed was \text{KE} = 63\; {\rm J}. All that much energy would have been converted when the sled is at its maximum height. Therefore, when h\; {\rm m} is the maximum height of the sled, the following equation would hold.

((137 + 68.1)\, h)\; {\rm J} = 63\; {\rm J}.

Solve for h:

(137 + 68.1)\, h = 63.

\begin{aligned} h &= \frac{63}{137 + 68.1} \approx 0.31\; \rm m\end{aligned}.

Therefore, the maximum height that this sled would reach would be approximately 0.31\; \rm m.

7 0
2 years ago
If a 30% discount is put on an item, and the sale price is $206.50, then what was the original price?
s2008m [1.1K]

Answer:

295

Step-by-step explanation:

.3 x 295 = 88.5

295 - 88.5 = 206.5

8 0
3 years ago
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