Answer:
816 cm²
Step-by-step explanation:
Surface area of the composite figure = (surface area of the larger rectangular prism + surface area of the smaller rectangular prism) - area of the side of the smaller rectangular prism that is joined to the bigger prism.
✔️Surface area of the larger rectangular prism:
Area = L*W*H = 20*5*6 = 600 cm²
✔️surface area of the smaller rectangular prism:
Area = L*W*H = 12*4*6 = 288 cm²
✔️area of the side of the smaller rectangular prism that is joined to the bigger prism.
Area = L*W = 12*6 = 72 cm²
Surface area of the composite = (600 + 288) - 72 = 888 - 72 = 816 cm².
Answer:
y = 4x + 1
Step-by-step explanation:
Given the equation y = 4x - 2, we need to find the equation parallel to this line. Note that for two equations to be parallel to each other, the must have the same slope
Standard form of an equation is y = mx + b
Compare;
mx = 4x
m = 4
Since the slope of the given equation is 4, the required equation must also have a slope of 4
Since we are not given an option, we can assume any equation with a slope of 4
y = 4x + 1 will be parallel to the given equation since they both have the same slope
<em>Note that the equation can be different so far they have the slope of 4</em>
The answer is 25m.
Height = 15
Length = 25
Height+lengthx2= 80(perimeter)
Height x length=375m2(area)
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
