Answer:
im answering this for the points and also u lied about how many points i would be getting. -.-
Step-by-step explanation:
answer is C i think
y = -2x + 9
y = 4x - 3
y is isolated in both equations, thus you may set the expressions (-2x + 9) and (4x - 3) equal to each other and solve for x.
-2x + 9 = 4x - 3
Subtract 9 from both sides.
-2x + 9 - 9 = 4x - 3 - 9
-2x = 4x - 12
Subtract 4x from both sides.
-2x - 4x = 4x - 12 - 4x
-6x = -12
Divide both sides by -6.
-6x/-6 = -12/-6
x = 2
Substitute 2 for x into one of the original equations to find y.
y = 4x - 3 (given)
y = 4(2) - 3 (substitute)
y = 8 - 3 (multiply)
y = 5 (subtract)
Plug x- and y-values into original equations to check work.
5 = -2(2) + 9
5 = - 4 + 9
5 = 5
5 = 4(2) - 3
5 = 8 - 3
5 = 5
Answer:
x = 2 and y = 5; (2, 5).
The system:
y = 3 x - 7
15 x - 5 y = 14
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Using the substitution method:
15 x - 5 · ( 3 x - 7 ) = 14
15 x - 15 x + 35 = 14
0 · x = 14 - 35
0 · x = - 21
x , y ∈ ∅
Answer:
D ) There is no solution.
Answer:
C= -5
D = 7
Step-by-step explanation:

Answer:
The probability is 
Step-by-step explanation:
If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:
If k=1

Because, in her first try she has n possibles options and just one give her a successful login.
If k=2

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.
If k=3

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.
Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n