Figure #1
use the smaller part of the figure with the dimensions of 1x2x3 and find the volume of that 1x2x3= 6m
find the area of the bigger part 3x6x3= 54m
54+6= 60m³
Figure #2
smaller part 2x2x7= 28m
bigger part 7x5x3= 105m
105+28= 133ft³
y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
Answer:
E
Step-by-step explanation:
Answer:
$2187.50 Commission for the sale
Step-by-step explanation:
Answer:
Step-by-step explanation: Not too sure how to explain it this is how you simplify it pretty sure
2x-y=7
+2x +2x add to both sides to get y alone because it has no friends
___________
-y=7+2x get rid of the negative on the y value
__________
y= -2x -7
