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Mathematics

2 answers:

Solnce55 [7]2 years ago

8 0

What are you stuck on because there’s no question?

abruzzese [7]2 years ago

7 0

Answer:

What do ya need help with?

Step-by-step explanation:

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if the product of 4 and a number is decreased by 12, the result is twice the opposite of the number. Find the number. EXPLAIN PL

ELEN [110]

Answer: The number is: "2 " .
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Explanation:
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Write the expression; which is an equation, as follows:
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" 4x − 12 = 2(-x) " ; in which "x" represents "the number for which we shall solve" .
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Note:

If the "number" = "x" ; the "opposite of the number" = " -x " ;
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Rewrite as: " 4x − 12 = -2x " ;
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→ Add "12" ; & add "2x" ; to EACH SIDE of the equation:

4x − 12 + 12 + 2x = -2x + 12 + 2x ;

to get: 6x = 12 ;
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Now, divide each side of the equation by "6" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
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6x / 6 = 12 / 6 ;

to get: x = 2 .
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Answer: The number is: "2 " .
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Let us check our answer, by plugging in "2" for "x" in our original equation:
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→ " 4x − 12 = 2(-x) " ;

Let us plug in "2" for "x" ; to see if the equation holds true; that is; if both side of the equation are equal; when "x = 2" ;

→ " 4(2) − 12 = ? 2(-2) ??

→ 8 − 12 = ? -4 ? ;

→ -4 = ? -4 ?? Yes!
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6 0

3 years ago

Please help me I'm stuck

AnnZ [28]

I don’t see any typing ?

6 0

2 years ago

Solve each equation (quadratic pattern)

dusya [7]

Answer: x = 2

Step-by-step explanation:

$2^{2x}-2^x-12=0\\\\\text{Let u = }2^x\\\\u^2-u-12=0\\(u-4)(u+3)=0\\\\u-4=0\quad and\quad u+3=0\\u=4\qquad and\quad u=-3\\\\\text{Substitute u with }2^x\\2^x=4\qquad and \quad 2^x=-3\\2^x=2^2\quad and\quad \text{not possible}\\\boxed{x=2}$

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Answer: x = 0

Step-by-step explanation:

$3^{2x}+3^{x+1}-4=0\\\\3^{2x}+3^x\cdot3^1-4=0\\\\\text{Let u = }3^x\\u^2+3u-4=0\\\\(u+4)(u-1)=0\\\\u+4=0\quad and\quad u-1=0\\u=-4\qquad and\quad u=1\\\\\text{Substitute u with }3^x\\3^x=-4\qquad and\quad 3^x=1\\\text{not possible}\ and\quad 3^x=3^0\\.\qquad \qquad \qquad \qquad \boxed{x=0}$

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Answer: No Solution

Step-by-step explanation:

$4^x+6\cdot 2^x+8=0\\\\2\cdot 2^x+6\cdot 2^x+8=0\\\\\text{Let u = }2^x\\2u+6u+8=0\\8u+8=0\\8u=-8\\u=-1\\\\\text{Substitute u with }2^x\\2^x=-1\\\text{not possible}$