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marusya05 [52]
3 years ago
14

Help me I'm stumped

Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0
What are you stuck on because there’s no question?
abruzzese [7]3 years ago
7 0

Answer:

What do ya need help with?

Step-by-step explanation:

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Why must bowhunters use broadhead points when hunting big game?
Stolb23 [73]
<span>Bowhunters must use broadhead points when hunting big game to ensure that they will be able to kill their game at the least time possible. The broadhead points causes massive blood loss to the prey as it cut through the vital organs and blood vessels of the animal.  

There are states that require a certain measurement of the broadhead point arrows. Theses arrows must be solidly built and must always be razor sharp to ensure quick penetration to the animals thick skin and layers of tissues. </span>
4 0
3 years ago
The ratio of two numbers is 2/3. The sum of the numbers is 105. What are the two numbers?
Pepsi [2]
A) x/y = 2/3
B) x + y = 105
Solving Equation A for y
A) y = 1.5x
Substituting A into B
B) x + 1.5x = 105
2.5x = 105
x = 42
y = 63


8 0
3 years ago
2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.
igomit [66]
The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
8 0
3 years ago
Solve 6 + 5 √ 2 4 9 − 2 x = 7
NISA [10]

6+5\sqrt{249}-2x=7 \\-2x=7-6-5\sqrt{249} \\-2x\approx-77.9 \\x\approx\frac{-77.9}{2}\approx38.95

Hope this helps.

7 0
3 years ago
Find the oth term of the geometric sequence 7, 14, 28, ...
yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

The ratio of all the adjacent terms is the same and equal to

r=2

now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

6 0
2 years ago
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