The boxplot required to answer the questions is attached below :
Answer:
The range for the Kentucky temperature :
(58.3 - 52.2) = 6.1
The range for the Illinois temperature :
(55 - 49.9) = 5.1
The IQR for the Kentucky temperature :
(57.3 - 54.5) = 2.8
The IQR for the Illinois temperature :
(53.3 - 50.9) = 2.4
Step-by-step explanation:
Range = maximum - minimum
Maximum and minimum values are given by the values at the end and start of the whisker.
The range for the Kentucky temperature :
(58.3 - 52.2) = 6.1
The range for the Illinois temperature :
(55 - 49.9) = 5.1
IQR = Q3 - Q1
Q3 = Value at the end of the box
Q1 = value of start of box
The IQR for the Kentucky temperature :
(57.3 - 54.5) = 2.8
The IQR for the Illinois temperature :
(53.3 - 50.9) = 2.4
To find:
Any two quadratic equations.
Solution:
The general form of a quadratic equation is:

Where, a,b and c are real number and a is non zero.
We know that a,b,c can take any values but a cannot be 0.
For a=1, b=1,c=1, we get


One quadratic equation is
.
For a=3,b=-1,c=5, we get


Therefore, the two quadratic equations are
and
.
Answer:
<h2>(-5, -28)</h2>
Step-by-step explanation:
The vertex form of a quadratic function <em>f(x) = ax² + bx + c</em>:
f(x) = a(x - h)² + k
(h, k) - coordinates of a vertex
We have <em>f(x) = x² + 10x - 3</em> in the vertex form <em>f(x) = (x + 5)² - 28</em>.
f(x) = (x - (-5))² + (-28) → h = -5, k = -28
Answer:
6
Step-by-step explanation:
Answer:21
Step-by-step explanation:2x21=42