The difference quotient of the function that has been presented to us will turn out to be 5.
<h3>How can I calculate the quotient of differences?</h3>
In this step, we wish to determine the difference quotient for the function that was supplied.
To begin, keep in mind that the difference quotient may be calculated by:
Lim h->0 
Now, for the purpose of the function, we need this:
Then we will have:

j(x) = 5x - 3
Then the following will be true:
Therefore, 5 is the value of the difference quotient for j(x) is %
Read the following if you are interested in finding out more about difference quotients:
brainly.com/question/15166834
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You plug -2 in for the function k(p) and add it to the function g(w), getting
(-2+3)*(-2-7)+(-2-5)^2=1*-9+49=40 for a - I challenge you to do B on your own!
The polynomial remainder theorem says that the remainder when dividing a polynomial

by a linear divisor

is simply

.
If

, then the remainder upon dividing by

is

You could also verify this by actually computing the quotient and remainder.
Asuuing yo meant (h,k)=(-5,1/2)
equation is

(h,k) is center and r=radious
given that (h,k)=(-5,1/2) and r=1
h=-5
k=1/2


if you wanted us to expand
x
²+y^2+10x-y+25.25=1