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lana66690 [7]
2 years ago
5

HELP I NEED HELP ASAP

Mathematics
1 answer:
asambeis [7]2 years ago
8 0

Answer:

D.\ (3,\frac{1}{8})

Step-by-step explanation:

Given

y = (\frac{1}{2})^x

Required

Points that lies on the above graph

From the given options, only option D lies on the point and the proof is as follows:

D.\ (3,\frac{1}{8})

This means that:

x = 3;\ y = \frac{1}{8}

Substitute x = 3;\ y = \frac{1}{8} in y = (\frac{1}{2})^x

\frac{1}{8} = (\frac{1}{2})^3

\frac{1}{8} = \frac{1^3}{2^3}

\frac{1}{8} = \frac{1}{8}

See that the values at the right and left hand side of the equation are the same.

This means that, D.\ (3,\frac{1}{8}) lies on y = (\frac{1}{2})^x

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6 0
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Read 2 more answers
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
3 years ago
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