Part A:
Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:

Part B:
If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:
The range for the cities in the south is 145 larger than the range for the cities in the north.
We find the range by subtracting the highest and lowest values; in the North, we have:
305 - 58 = 247
In the South, we have:
503 - 111 = 392
The difference in the ranges is 392 - 247 = 145.
Answer:
The answer is 21.5625
Step-by-step explanation:
The reason is because it first says 5 miles=8 km so that helps us right there.We divide 34.5 by 8 which will give us 4.3125.Then you have to multiply that by 5 which will give us 21.5625.
Answer:
look im sorry but ur on your own
Step-by-step explanation:
Answer: Distance is 8.9
Step-by-step explanation:



Add it all together

Square 80
