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Zanzabum
3 years ago
15

HURRYYYYY

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0

Answer:

B is correct.

Step-by-step explanation:

Quadratic Expression (Standard Form) is:

\displaystyle \large{a {x}^{2}  + bx + c}

To say it simply, the expression must have 2 as the highest degree.

This means that if there are any higher or lower degrees than 2 then they are not quadratic expression.

A choice is not quadratic expression because it has 1 as the highest degree.

B choice is correct because 2 is the highest degree.

C choice is wrong because 3 is the highest degree.

D choice is wrong because it is not a polynomial.

Therefore, B is correct.

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The value of X is 80
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6.) Alan, Becky, Jesus, and Mariah are four students in the chess club. If two of these students will be selected to represent t
Artist 52 [7]

Let's begin by listing out the information given to us:

There are four students: n = 4

Number of students to be selected: r = 2

To calculate the combination of 2 students to be chosen, we use:

\begin{gathered} ^4C_2=\frac{n!}{(n-r)!}=\frac{4!}{(4-2)!}=\frac{4!}{2!} \\ ^4C_2=\frac{4\cdot3\cdot2\cdot1}{2\cdot1}=\frac{4\cdot3}{1}=12 \\ ^4C_2=12 \end{gathered}

Therefore, there 12 possible combinations from these

3 0
1 year ago
The width and height of a television screen are 80 in and 45 in, respectively. Find the area of this television screen.
r-ruslan [8.4K]

Answer: C: 3600


Step-by-step explanation: When trying to find the area of a rectangle or a square all you need to do is multiply the Length and the Width (L * W). The equation you need to solve this is 80 * 45 = x. The answer is 3600.


4 0
3 years ago
Read 2 more answers
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

5 0
3 years ago
Evaluate the expression below.<br><br> 15 ÷ (5 - 2) + 4 =
lana [24]

Answer:

Step-by-step explanation:

This is an order of operations question. First in PEMDOS you want to do your parenthesis, turn (5-2) into 3,

15 ÷ 3 + 4 

Then do your divison, turning 15 ÷ 3 into 5

5 + 4 

Then finish with 5 + 4

The answer is 9



3 0
2 years ago
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