Box of 24 chocolate contains 6 cream-filled. What is the probability of randomly selecting a cream filled

Mathematics

1 answer:

kifflom [539]2 years ago

5 0

The probability of randomly selecting a cream filled

Chocolate is 1/4

Probability is the likelihood of an event will occur
Probability of an event is find out by divide the number of favorable outcomes by the total number of possible outcomes.
The simplest example is flipping of a coin.
There are only two possible outcomes when you flip a coin. It wiil be either heads or tails.
Total probability is always lie between 0 and 1

Let E be the event of selecting cream filled chocolate.

Number of favourable outcome = 6

Total number of possible outcome = 24

Probability if selecting a cream filled chocolate = 6/24

= 1 / 4

Hence, the probability of randomly selecting a cream filled chocolate is 1/4

Learn more about probability here:

brainly.com/question/24756209

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Which is bigger: 17.5% or 1/6

elena-s [515]

In order to find this out, let's convert both of them into percents. Since 17.5 is already a percent, we only have to convert 1/6 into a percent. To convert 1/6 into a percent, you have to divide the numerator by the denominator. If you do that, you will get 0.1666..... as a repeating decimal. Now, multiply the decimal by 100 or just move the decimal 2 spaces to the right to get the percent. If you do that, you will get 16.6%. Since it is a repeating decimal, you can round it to 16.7%. So, 17.5% is larger than 1/6.

Hope it helps :)

6 0

3 years ago

Read 2 more answers

The resting heart rate for an adult horse should average about µ = 47 beats per minute with a (95% of data) range from 19 to 75

KatRina [158]

Answer:

a. 0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. 0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. 0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean:

$\mu = 47$