A- 6/25 you can use A 4 times the other letters you can ether use 2 time or 1 time.
Answer:
Option (A)
Step-by-step explanation:
By satisfying the equation of a function 'f' by each coordinates given in the options we can get the point which lies on the graph of f(x) = 
Option (A). (1, 10)
f(1) = 
10 = 10
True.
Therefore, point (1, 10) lies on the graph.
Option (B). (0, 10)
f(0) = 
10 = 2
Not true.
Therefore, point (0, 10) doesn't lie on the graph.
Option (C). (10, 1)
f(10) = 
1 = 19531250
Not true.
Therefore, point (10, 1) doesn't lie on the graph.
Option (D). (0, 0)
f(0) = 
0 = 2
Not True.
Point (0, 0) doesn't lie on the graph.
Option (A) will be the answer.
R = 10, T = 20
OK. Calculate the length of segment RT:
|RT| = |20 - 10| = |10| = 10
Divide |RT| into a ratio of 2:3
2 + 3 = 5
10 : 5 = 2
Therefore we have
|RS| = 2 · 2 = 4 and |ST| = 3 · 2 = 6 (4 + 6 = 10 CORRECT)
T = R + 4 and T = T - 6
T = 10 + 4 = 14; T = 20 - 6 = 14 CORRECT
<h3>Your answer is T = 14.</h3>
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