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2 years ago

A container of cream cheese weighs 250 grams, which is equivalent to 8.8 ounces. Calculate the missing conversions

Mathematics

1 answer:

exis [7]2 years ago

5 0

11 oz = 311.845 or 311.8 grams
1,000grams = 35.274 or 35.3 oz

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Which of these describes information that can appear in a consumer’s credit report?

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I believe the answer is D. A credit report covers info on loan paying history. I was stuck between b and d but then realized it said the company gave a loan while your own credit history covers what you have paid or loaned. Hope this helps, have a nice day.

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Factor the expression.<br> 20b + 35 =<br> (Factor completely.)

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I think it would be 5(4b+7)

Step-by-step explanation:

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2 years ago

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

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2 years ago

Which literal equation is not equivalent to x equals two y plus z ?

abruzzese [7]

Answer:

x minus z equals two times y

Step-by-step explanation:

x minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times yx minus z equals two times y

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