Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
5cm
Step-by-step explanation:
5cm * 5cm = 25cm
The answer to this question is true.
Answer: It is letter C. 1/22
Step-by-step explanation:
Change 2 3/4 to an improper fraction to get 11/4, then multiply 1/8 by the reciprocal of 11/4 which is 4/11.
1/8 x 4/11= 4/88
4/88 simplified = 1/22